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Papessa [141]
3 years ago
14

Ben runs around the track at a pace of 1 lap every 80 seconds. Sally runs on the track in the opposite direction. The two meet e

very 30 seconds. How long does it take Sally to run each lap around the track?
Mathematics
1 answer:
disa [49]3 years ago
5 0
48 seconds, Consider what happens between one time that Ben and Sally meet and the next. During this period Ben runs 30 (seconds)/80 (seconds/lap) = 3/8 of a lap. So Sally runs 5/8 lap in the same time. Her speed is therefore 5/8 (laps)/ 30(seconds) which amounts to 1 (lap)/ 48 (seconds).
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Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds using percentages how much better was her second lap
julsineya [31]

Answer:

Her second lap was <u>8%</u> better when compared to her first lap.

Step-by-step explanation:

Given:

Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds.

Now, to find how much better was her second lap when compared to her first lap.

Emily ran her first lap in 75 seconds.

Emily ran her second lap in 69 seconds.

So, we get the difference in seconds:

75-69=6\ seconds.

<u><em>Thus, in her second lap she was 6 seconds better than first.</em></u>

Now, to get the percentage of her first lap better than second:

\frac{6}{75}\times 100

=0.08\times 100

=8\%.

Therefore, her second lap was 8% better when compared to her first lap.

7 0
3 years ago
Is this non-linear yes or no
Serjik [45]

It's linear and equation of the function is :

f ( x ) = 2x - 1

3 0
2 years ago
The sink in Josh’s art studio measures 16 inches by 15 inches by 6 inches. A second sink used just for paint brushes has a simil
marin [14]
Linear scale factor =1/2
volume scale factor=(1/2)³=1/8
the volume of the larger figure will be:
volume=length*width*height
volume=16×15×6
volume=1440 cubic inches
thus volume of the small sink will be:
1/8×1440
=180 cubic inches
3 0
2 years ago
55%of92 in percent time
solmaris [256]
That would be <span>50.6, I believe. You multiply 92 by 55% or .55 and get 50.6 </span>
6 0
3 years ago
Consider the sequence 10, 2..
romanna [79]

Answer:  see below

<u>Step-by-step explanation:</u>

1) 10, 2, 1.2, 1.12, 1.112, 1.1112

t_n=\dfrac{t_{n-1}}{10}+1

t₁ = 10

t₂ = 10/10 + 1    = 2

t₃ = 2/10 + 1     = 1.2

t₄ = 1.2/10 + 1   = 1.12

t₅ = 1.12/10 + 1  = 1.112

t₆ = 1.112/10 + 1 = 1.1112

2)  10, 2, -2, -4, -5, -5.5, ...

t_n=\dfrac{t_{n-1}}{2}-3

t₁ = 10

t₂ = 10/2 - 3 =   2

t₃ = 2/2 - 3  =  -2

t₄ = -2/2 - 3 =  -4

t₅ = -4/2 - 3 =  -5

t₆ = -5/2 - 3 = -5.5

8 0
3 years ago
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