-- The original price was $82.
-- The dealer knocked ($82 - $65.60) = $16.40 off of the price because
he loves his customers so much and he wanted to make their lives easier.
-- The amount he knocked off is ( 16.40 / 82 ) = 0.2 = <em>20%</em> of the original price.
==========================================
Check:
If he reduced the original price 20%, then 80% of it must have been left.
80% of the original price = 0.8 x $82 = $65.60 It checks. <em>yay!
</em>
You multiply all three of these numbers to get an answer of 471.25
7 centimeters is a possible length for the third side ⇒ B
Step-by-step explanation:
Let us revise the triangle Inequality Theorem
- The sum of the lengths of any 2 sides of a triangle must be greater than the length of the third side
- To prove that by easy way add the smallest two sides, if their sum greater than the third side,then the sides can form a triangle
Assume that the length of the third side is x cm
∵ The length of two sides are 7 cm and 10 cm
∵ The length of the third side is x cm
- Put the sum of x and 7 greater than 10 ( x and 7 are the smallest sides)
∴ x + 7 > 10
- Subtract 7 from both sides
∴ x > 3
- Put the sum of 7 and 10 greater than x (7 and 10 are the smallest sides)
∵ 7 + 10 > x
∴ 17 > x
∴ x < 17
- By using one inequality for x (combined the two inequalities in one)
∴ 3 < x < 17
That means the length of the third side is any number between 3 and 17
There is only one answer between 3 and 17
∵ 7 is between 3 and 17
∴ The length of the third side could be 7 cm
7 centimeters is a possible length for the third side
Learn more:
You can learn more about triangles in brainly.com/question/4599754
#LearnwithBrainly
Yes, the line passes the vertical line test (no x-values are repeated)
You have to estimate the slope of the tangent line to the graph at <em>t</em> = 10 s. To do that, you can use points on the graph very close to <em>t</em> = 10 s, essentially applying the mean value theorem.
The MVT says that for some time <em>t</em> between two fixed instances <em>a</em> and <em>b</em>, one can guarantee that the slope of the secant line through (<em>a</em>, <em>v(a)</em> ) and (<em>b</em>, <em>v(b)</em> ) is equal to the slope of the tangent line through <em>t</em>. In this case, this would be saying that the <em>instantaneous</em> acceleration at <em>t</em> = 10 s is approximately equal to the <em>average</em> acceleration over some interval surrounding <em>t</em> = 10 s. The smaller the interval, the better the approximation.
For instance, the plot suggests that the velocity at <em>t</em> = 9 s is nearly 45 m/s, while the velocity at <em>t</em> = 11 s is nearly 47 m/s. Then the average acceleration over this interval is
(47 m/s - 45 m/s) / (11 s - 9 s) = (2 m/s) / (2 s) = 1 m/s²
