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3 years ago

13

A baseball is dropped from a stadium seat that is 73 feet above the ground. Its height s in feet after t seconds is given by s(t

)=73−16t^2. Estimate how long it takes for the baseball to strike the ground.

1 answer:

lisov135 [29]3 years ago

8 0

0 = 73 - 16t^2
16t^2 = 73
4^2*t^2 = 73
(4t)^2 = 73
<span>sqrt(4t^2) = sqrt(73) </span>
4t = 8.5440
<span>t = 2.136</span>
ANSWER: 2.1 seconds

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Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given expression is

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So, on substituting the values evaluated above, we get

$\rm \: = \: \displaystyle\lim_{n \to \infty} \frac{\dfrac{ {n}^{n} - 1}{1 - \dfrac{1}{n} }}{{n}^{n}\bigg[1 +\bigg[1 - {\dfrac{1}{n}\bigg]}^{n} + \bigg[1 - {\dfrac{2}{n}\bigg]}^{n} + - - - + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]}$

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Pachacha [2.7K]

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