13/90
so there are 90 two digit numbers.
there are a 13 two digit numbers divisible by 7. so there is a 13/90 probability of a two digit number being selected at random that’s divisible by 7
The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Answer:
Well, first, you have to find out how much food each person needs. Assuming everyone eats the same amount, you divide 24 by 6, getting 4 meatballs per person. Then you divide the 4 pounds of pasta by 6, getting .75 pounds of pasta per person. Then you multiply both of those numbers, 4 and .75 by 8, since that is how many people will be eating that night. You get 32 meatballs, and 6 pounds of pasta.
Step-by-step explanation:
Hope this helps.
Answer:
d.156.
x+24=180 ( being staright angle)
What was your last question, I might be able to help.
