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s2008m [1.1K]
3 years ago
13

What is the first year in which franklins sign shows a larger number than chester’s sign

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0
This is the answer for the first year

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Work out the mean for the data set below:
mafiozo [28]

Answer:

3.4 + 5.2 + 4.7 + 3.5 + 0.5

= 17.3

There are a total of 5 numbers

17.3 / 5

= 3.46

8 0
3 years ago
Draw a quick picture to show the number 24. Then draw a quick picture to show 24 after you have regrouped 1 ten as 10 ones. Expl
Andrews [41]
<span>Just draw 24 circles, or sticks, or stars, and then draw 10 little squares in a row twice, and 4 separate square. In the explanation say that there are 24 of whatever shape or thing you decided to draw and, for the regrouped say that 10+10+4=24 </span>
7 0
3 years ago
Read 2 more answers
The answer to all of these problems
-BARSIC- [3]
1) area of a cicular pool
area of a circle=πr^2   d=2.5 then r=2.5/2
A=3.14 *(2.5/2)^2
A=4.906m^2 A=4.9m^2

2) arae of a coin 
<span>(if i read it right d=15mm?)
</span>A=πr^2   d=15 then r=15/2
A=3.14*(15/2)^2 =176.6mm^2


Rest all are same problems u try to solve it
4 0
3 years ago
Which is not a representation of the equation y = 0.5x - 2?
Studentka2010 [4]

Answer:

D is incorrect so ur answer is D

8 0
3 years ago
Write an equation of the line containing the point (6,-4) and perpendicular to.the line y=-2x-3
igor_vitrenko [27]

Answer:

y=\frac{1}{2}x-7

Step-by-step explanation:

So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.

First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

m_1\cdot m_2=-1

Plug -2 for one of the slopes.

-2\cdot m_2=-1

Divide by -2 to find the slope of our line.

m_2=1/2

Thus, our line needs to have a slope of 1/2.

Now, let's use the point-slope form. The point-slope form is given by:

y-y_1=m(x-x_1)\\

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

y-(-4)=\frac{1}{2}(x-6)\\

Simplify and distribute:

y+4=\frac{1}{2} x-3

Subtract 4 from both sides:

y=\frac{1}{2}x-7

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.

5 0
3 years ago
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