All categories

3 years ago

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Mathematics

1 answer:

Ivan3 years ago

3 0

Answer:

a. (0,-5)

Step-by-step explanation:

You might be interested in

−6x^2−1 and x+9 help will mark brainliest.

Varvara68 [4.7K]

Answer:

-6x^2+x+8

Step-by-step explanation:

Add -1 and 9 because they are the only like terms

8 0

3 years ago

A right square pyramid has a slant height of 10 feet, and the length of a side

kotykmax [81]

Step-by-step explanation:

take the base square. find the diagonal

16^2+16^2 = 2*16^2= d^2

d= 16√2

half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10

6 0

2 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago

Geometry help will give brainliest

Natali [406]

6x + 4x + 10 = 180
10x = 170
x = 17

mCA = 4(17) + 10 = 68 + 10 = 78

Answer:
mCA = 78°

8 0

3 years ago

A web server hosting company advertises 99.999 percent guaranteed network uptime. (a) how many independent network servers would

miv72 [106K]

The solution for this problem would be:
Given that there is 99.999%.

Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n

Therefore, (1-p) ^n = 0.00001

a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer

1-(1-.97)^3= 0.99999 + 0.0001 = 1

b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer

1-(1-.88)^3= 0.99 + 0.0001 = approx 1

4 0

3 years ago