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Oksi-84 [34.3K]
3 years ago
15

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Mathematics
1 answer:
Ivan3 years ago
3 0

Answer:

a. (0,-5)

Step-by-step explanation:

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−6x^2−1 and x+9 help will mark brainliest.
Varvara68 [4.7K]

Answer:

-6x^2+x+8

Step-by-step explanation:

Add -1 and 9 because they are the only like terms

8 0
3 years ago
A right square pyramid has a slant height of 10 feet, and the length of a side
kotykmax [81]

Step-by-step explanation:

take the base square. find the diagonal

16^2+16^2 = 2*16^2= d^2

d= 16√2

half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10

6 0
2 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
Geometry help will give brainliest
Natali [406]
6x + 4x + 10 = 180
10x = 170
   x = 17

mCA = 4(17) + 10 = 68 + 10 = 78

Answer:
mCA = 78°
8 0
3 years ago
A web server hosting company advertises 99.999 percent guaranteed network uptime. (a) how many independent network servers would
miv72 [106K]
The solution for this problem would be:
Given that there is 99.999%.

Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n

Therefore, (1-p) ^n = 0.00001


a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer


1-(1-.97)^3= 0.99999 + 0.0001 = 1


b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer


1-(1-.88)^3= 0.99 + 0.0001 = approx 1
4 0
3 years ago
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