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Nana76 [90]
3 years ago
13

A batch of 484 containers for frozen orange juice contains 7 that are defective. Two are selected, at random, without replacemen

t from the batch. a) What is the probability that the second one selected is defective given that the first one was defective? Round your answer to five decimal places (e.g. 98.76543).
Mathematics
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

1.242% probability that the second one selected is defective given that the first one was defective

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have

484 containers

7 are defective

a) What is the probability that the second one selected is defective given that the first one was defective?

After the first one was selected(defective), we have

483 containers

6 defective

6/483 = 0.01242

0.01242 = 1.242% probability that the second one selected is defective given that the first one was defective

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Step-by-step explanation: i had to take this test ): luck

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What is 10 more than 451
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<span>To find 10 more than 451 is very simple, simply add 10 to 451 to get 461.</span>
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Jessica made 8 out of 24 free throws. Bob made 5 out of 20 free throws. Who has the highest free throw ratio ?
Gnoma [55]
8 out of 24 = 1 out of 3

5 out of 20 = 1 out of 4

1/3 is larger that 1/4
Jessica has the largest ratio
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1 year ago
A student got 85% on a math test with 40 problems. How many did the student get correct?
dalvyx [7]

Answer:

The student got 34 of the 40 questions correct.

Step-by-step explanation:

85% of 40 is 34.

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3 years ago
Read 2 more answers
Tentukan persamaan garis yang di wakili ruas garis AB,BC,CD dan AD! <br>tolong kak
Ann [662]

Answers:

1. AB: y = - 2x - 6

2. BC: y = x - 3

3. CD: x = 3

4. AD: y = (3/7) x +26/7


Solution:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)


1. AB

A=(-4,2)=(xa, ya)→xa=-4, ya=2

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

mab=(yb-ya)/(xb-xa)

mab=(-4-2)/(-1-(-4))

mab=(-6)/(-1+4)

mab=(-6)/(3)

mab=-2

y-ya=mab (x-xa)

y-2=-2(x-(-4))

y-2=-2(x+4)

y-2=-2x-8

y-2+2=-2x-8+2

y=-2x-6


2. BC

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

C=(3,0)=(xc, yc)→xc=3, yc=0

mbc=(yc-yb)/(xc-xb)

mbc=(0-(-4))/(3-(-1))

mbc=(0+4)/(3+1)

mbc=(4)/(4)

mbc=1

y-yc=mbc (x-xc)

y-0=1 (x-3)

y=x-3


3. CD

C=(3,0)=(xc, yc)→xc=3, yc=0

D=(3,5)=(xd, yd)→xd=3, yd=5

mcd=(yd-yc)/(xd-xc)

mcd=(-4-0)/(3-3)

mcd=(-4)/(0)

mcd= Infinite (Vertical line)

Equation vertical line: x=xc=xd

x=3


4. AD

A=(-4,2)=(xa, ya)→xa=-4, ya=2

D=(3,5)=(xd, yd)→xd=3, yd=5

mad=(yd-ya)/(xd-xa)

mad=(5-2)/(3-(-4))

mad=(3)/(3+4)

mad=3/7

y-ya=mad (x-xa)

y-2=(3/7)(x-(-4))

y-2=(3/7)(x+4)

y-2=(3/7)x+12/7

y-2+2=(3/7)x+12/7+2

y=(3/7)x+(12+7(2))/7

y=(3/7)x+(12+14)/7

y=(3/7)x+26/7


8 0
3 years ago
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