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Norma-Jean [14]
3 years ago
14

Niu earned $312 on an investment of $800. How much would $1100 have earned in the same

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

Answer:

429

Step-by-step explanation:

312/800 = .39

1100 x .39 = 429

mel-nik [20]3 years ago
5 0

Answer:

$429

Step-by-step explanation:

--------------------

\frac{312}{800} =\frac{x}{100}

Cross multiply

800x=31200

Divide both sides by 800

x=39

So, Niu earned 39% on the investment of $800

So, let's find out how much $1,100 would have earned him in the same investment.

--------------->>>>

\frac{x}{1100}=\frac{39}{100}

Cross multiply

100x=42900

Divide both sides by 100

x=429

--------------------

This means that Niu $1,100 would have earned Niu $429 in the same investment.

Hope this is helpful

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This quadratic equation lokks like a upside down parabolla
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The "a" in the vertex form "<span>y = a(x – h)2 + k</span>" of the quadratic is the same as the "a" in the common form of the quadratic equation, "<span>y = ax2 + bx + c</span><span>".
</span>

<span>To find the vertex, I look at the coefficients a<span>, </span>b<span>, and </span>c. The formula for the vertex gives me:<span>Y= -0.025s2 + 2.45s - 30
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3 years ago
Read 2 more answers
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