Find the gcf of the pair of numbers. 35 and 21 the gcf is .

Mathematics

2 answers:

makvit [3.9K]2 years ago

8 0

You r GCF would be 7 because it multiplies both those numbers

astraxan [27]2 years ago

4 0

Answer:

GCF=7

Step-by-step explanation:

You might be interested in

The ratio of lollipops to pieces of bubble gum at the party is 2 to 3. There are 24 lollipops. What is the total number of lo

disa [49]

Answer: 40

Step-by-step explanation: first make the ratio into a fraction, 2/3

then make 24 into a fraction with the numerator as a variable and the denominator as 24, x/24

then cross multiply 2 and 24.

2x24=48

then divide 48 by 3, 16.

last add the number of lollipops to 16 and the answer is 40.

5 0

2 years ago

Read 2 more answers

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$