$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=0(x-6)\implies y+8=0\implies y=-8$

5 0

3 years ago

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The graph shows a journey in a car Help Fast!!!

Sever21 [200]

Answer: i think the answer would be c

i hope this helps you out!

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST.

kari74 [83]

Answer:

Choice D

Step-by-step explanation:

For this one I would find if the point lands on the line.

Choice A:

What we have to do is to plug in -4 for x and 4 for y.

$y=2x+10\\(4)=2(-4)+10\\4=-8+10\\4\ne2$

The point is not on this line so this cannot be it.

Choice B:

We pug what we know again.

$y=\frac{1}{3}x+1\\(4)=\frac{1}{3}(-4)+1\\(4)=-\frac{4}{3}+1\\4\ne-\frac{1}{3}$

The point is not on this line so it can't be it.

Choice C:

We pug in what we know again.

$y=3x-9\\(4)=3(-4)-9\\(4)=-12-9\\4\ne-21$

The point is not on this line so it can't be it.

The next one has to be it, but we'll check it just in case.

Choice D:

We plug in what we know again.

$y= \frac{1}{2}x+6\\(4)=\frac{1}{2}(-4)+6\\(4)=-2+6\\4=4$

The point is on this line so this is the line.

3 0

3 years ago