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3 years ago

Simplify the above question

Mathematics

1 answer:

ankoles [38]3 years ago

6 0

Answer:

0.75417552

reduced equals 0.75

Step-by-step explanation:

log(55/2)

log(81)

Decimal Form: 0.7541755

this answer is the anser if you are dividing log 10 and 27 1/3 by log 10 81

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The value of a professor basketball players autograph rose 30% in the las year.It is now worth $286.00. What was it worth a year

sineoko [7]

Answer:

$220 dollars

Step-by-step explanation:

a = p * w (the percentage formula)

subsitute. It rose by 30 % since last year so you're going to put 1.30 (30% -> 0.30 then add 1)

286 = 1.30 * w

solve.

w = 220

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3 years ago

Which expression fits the description

inessss [21]

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3 years ago

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Given f(x)=-2x-1, solve for x when f(x)=-7

Svetlanka [38]

Answer:

The answer is -15.

Step-by-step explanation:

1. 2x - 1

2. 2(-7) - 1

3. (-14) - 1

4. -15

By plugging in our x value, we are able to use PEMDAS to multiply 2 and the value of x and then, we subtract 1 from the value we got from step 3 to get -15.

5 0

2 years ago

Sold the equation. Round to the nearest hundredth. 17 · <img src="https://tex.z-dn.net/?f=1.8%5E%7B-x%2B7%7D%20%3D%205"

svetlana [45]

Answer:

Final answer is approx x=4.26.

Step-by-step explanation:

Given equation is $1.8^{-x+7} = 5$

Now we need to solve equation $1.8^{-x+7} = 5$ and round to the nearest hundredth.

$1.8^{-x+7} = 5$

$\log(1.8^{-x+7}) = \log(5)$

$(-x+7)\log(1.8) = \log(5)$

$(-x+7) = \frac{\log(5)}{\log(1.8)}$

$(-x+7) = \frac{0.698970004336}{0.255272505103}$

$-x+7 = 2.73813274192$

$-x = 2.73813274192-7$

$-x =−4.26186725808$

$x =4.26186725808$

Round to the nearest hundredth.

Hence final answer is approx x=4.26.

4 0

3 years ago

A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take

Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - α)% confidence interval for population proportion P is:

$CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}$

The information provided is:

x = number of students who responded as"yes" = 70

n = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

$p=\frac{x}{n}$

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0

3 years ago

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Simplify the above question​

Simplify the above question