Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
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<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
Answer: (-8, -80)
<u>Step-by-step explanation:</u>
y = 10x
y = -3x - 104
Substitute "y" with "10x" into the second equation, then solve for x:
10x = -3x - 104
13x = -104 <em>added 3x to both sides</em>
x = -8 <em>divided both sides by 13</em>
Next, substitute -8 for x into the first equation to solve for y:
y = 10(-8)
= -80
This are the right steps
Step 1: first you divide the both size by 7 because there is 7 a's
7a/7 = 28/7
Step 2: You solve the equation
7a/7= a. 28/7 = 4
So, the answer is a = 4
not 7 = 4
Answer:
A, B, and D
Step-by-step explanation:
Only the functions that have x by itself between the absolute value signs (A, B, and D) are symmetric with respect to the y-axis .
Placing a constant outside the absolute value signs moves the function up or down the y-axis but retains the symmetry.
Adding a constant inside the absolute value signs (as in C and E) moves the axis of symmetry to the left or right of the y-axis.
In the diagram, both A and B are symmetric with respect to the y-axis, but C has been shifted three units to the left.
