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2 years ago

Please help for number 8 I don't understand.

Mathematics

1 answer:

Ksju [112]2 years ago

8 0

Answer:

8a. x = 16√3

8b. y = 8√3

Step-by-step explanation:

8a. Determination of the value of x

Adjacent = 24

Hypothenus = x

Angle θ = 30°

The value of x can be obtained by using cosine ratio as illustrated below:

Cos θ = Adjacent /Hypothenus

Cos 30 = 24 / x

√3/2 = 24/x

Cross multiply

x × √3 = 2× 24

x × √3 = 48

Divide both side by √3

x = 48/√3

Rationalise

x = 48/√3 × √3/√3

x = 48√3 / √3 × √3

x = 48√3 / 3

x = 16√3

8b. Determination of the value of y

Opposite = y

Adjacent = 24

Angle θ = 30°

The value of y can be obtained by using Tan ratio as illustrated below:

Tan θ = Opposite / Adjacent

Tan 30 = y / 24

1 / √3 = y /24

Cross multiply

y × √3 = 1 × 24

y × √3 = 24

Divide both side by √3

y = 24 /√3

Rationalise

y = 24 /√3 × √3/√3

y = 24 ×√3 / √3 × √3

y = 24√3 / 3

y = 8√3

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Read 2 more answers

12n^3 + 16n^3 can someone please help me with this?

vodka [1.7K]

Answer:

$4n^{3} (3n^{2} + 4)$

Step-by-step explanation:

Assuming the problem is asking you to factor out the formula, it can be done easily by finding a common number with the two givens.

4 goes into both 12 and 16 evenly, so we will use this to factor. But that's not all, we have the n-variable to worry about.

Look at the n-variable exponents in the problem, take the highest power that can go be subtracted from both and use that. We have a $n^{5}$ and $n^{3}$ . Since 5 can't go into 3, we must use 3 to factor.

Our factoring variable will therefore be $4n^{3}$ . Now, use this to simply divide and get the answer:

$( 12n^{5} + 16n^{3} ) / 4n^{3} = 4n^{3}(3n^{2} + 4)$

So how did we get this? For the whole numbers, we have to divide: (12/4, 16/4). Next, we have to minus the exponents since we are dividing.

When dividing the 12 and 4, minus the $n^{5}$ and $n^{3}$ to get $n^{2}$ . Get rid of the $n^{3}$ term for the 16 and leave the 4. And there's your answer!