Answer:
x = 3/2
Step-by-step explanation:
(2x + 3)2 – 4(2x + 3) - 12 = 0
Simplify the equation then isolate for x.
Distribute over brackets:
(4x + 6) – (8x + 12) - 12 = 0
Combine like terms:
4x + 6 – 8x + 12 - 12 = 0
6 - 4x = 0
Isolate x:
6 = 4x
6/4 = x
Reduce the fraction:
6/4 = x <= divide top and bottom by "scale factor" of 2
3/2 = x
x = 3/2 <= having x on the left side is standard
Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
0.06
Step-by-step explanation:
Answer:
No they're not equivalent
Step-by-step explanation:
5(x - 9) + 2x -1 -5(9 - x) - 2x
5x - 45 + 2x - 1 5x - 45 - 2x
7x + 46 does not equal 3x - 45
Explaining isnt my specialty, sorry
