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2 years ago

One inch is 25.4 millimeters. Write 25.4 millimeters as a mixed number in simplest form.

Mathematics

2 answers:

Ronch [10]2 years ago

5 0

25 2/5
Twenty five and two fifths

jarptica [38.1K]2 years ago

3 0

25 2/5 is the answer to your question. I hope this helps!

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Greg paid $33 for 2 shirts and $48 for 3 shirts including a fixed shipping fee assuming the same function applies to any numbers

wel

Answer:

15 Dollars

Step-by-step explanation:

If you take the shipping price (3 dollars) off you get 15 per shirt

8 0

3 years ago

At 8:00 a.m., the temperature was −6°F. By noon, the temperature had risen by 9°F. What was the temperature at noon?

olya-2409 [2.1K]

The answer is orange because I think that is the answer

8 0

3 years ago

A container shaped as a rectangular prism can hold 756 wooden cube blocks with edge lengths of 13 ft.

pychu [463]

Answer:

the volume of the container is $28\ ft^{3}$

Step-by-step explanation:

we know that

To find the volume of the container calculate the volume of one wooden cube block and multiply by 756

The volume of one cube is equal to

$V=(1/3)^{3}= (1/27)\ ft^{3}$

the volume of the container is equal to

$V=(1/27)*756=28\ ft^{3}$

4 0

3 years ago

Read 2 more answers

Please helppp meee I need it done noww

bearhunter [10]

Answer:

7/2

Step-by-step explanation:

3 wholes is equal to 6 halves plus a half equals 7 halves

6 0

3 years ago

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for y with respect to x, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

3 years ago