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pentagon [3]
3 years ago
13

ivided by (-9)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Anton [14]3 years ago
3 0

Answer:

your answer is -6.1111111111111

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Help me with this for geometry please
Kamila [148]

Answer:

57 units

Step-by-step explanation:

So the step is we need to find out the scale factor

And the scale factor is 24/8 =3

So the parameter of ANG is

19×3

=57

8 0
3 years ago
What is the volume of a hemisphere with a radius of 26.7 m, rounded to the nearest tenth of a cubic meter?
attashe74 [19]

Answer:

39,865.1m^3

Step-by-step explanation:

a hemisphere is half a sphere.

And if the formula for the volume of a sphere is:

V=\frac{4\pi r^3}{3}

we must calculate the volume of the sphere and in the end divide by two to find the volume of the hemisphere.

Since the radius is:

r=26.7m

substituting this into the formula for volume:

V=\frac{4\pi (26.7m)^3}{3} \\\\V=\frac{4(3.1416)(19,034.163m^3)}{3} \\\\V=79,730.12m^3

this is the volume of the total sphere, thus the volume of a hemisphere is:

\frac{V}{2}=\frac{79,730.12m^3}{2}\\  =39,865.06m^3

rounding to the nearest tenth:

39,865.1m^3

8 0
4 years ago
Read 2 more answers
the scale from a square park to a drawing of the park is 5 m to 1 cm the actual park has an area of 1,600 m² what is the area of
ludmilkaskok [199]

Answer:

<h2>64 cm²</h2>

Step-by-step explanation:

given:

the scale from a square park to a drawing of the park is 5 m to 1 cm

the actual park has an area of 1,600 m²

find:

what is the area of the drawing of the park​

solution:

drawing scale is 5m : 1cm

<u>1,600 m² </u> = <u>      5² m²  </u>    

   x                  1² cm²

cross multiply:

5² m² x = 1600 m² (1 cm²)

x =<u> 1600 m² </u>

      5² m²

x = 64 cm²

therefore, the area of a square park in the drawing is 64 cm²

5 0
3 years ago
For which value of m is 4/16 = m/24 a proportion
AnnyKZ [126]

Answer:

A is the answer

Step-by-step explanation:

What you do is you cross multiply 24x4 which equals 96. Then, you divide by 16. Which gives us: m = 6

4 0
3 years ago
Evaluate Integral: 2sin(2x) from 0, pi/2
Neko [114]
Integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2 
8 0
3 years ago
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