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3 years ago

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Mrs. Myles gave the same test to both her first and third period class. In first period, the median was 75 and the range was 30.

In third period, the median was 80 and the range was 60. Which is a true statement?

2 answers:

Ludmilka [50]3 years ago

8 0

Answer:

A

Step-by-step explanation:

Dennis_Churaev [7]3 years ago

7 0

Answer:

The range is the difference between the biggest and smaller values of a set. The median is the middle value of a set. So we cannot say were the lowest score was found, comparing the median and ranges, because it could be that some repeated value very low or high is biasing the median, we could do it with the mean perhaps. So the proposal is false.

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Is relation t a function? Is the inverse of relation t a function?

bonufazy [111]

<u>Answer:</u>

Hence, Relation t is a function. The inverse of relation t is a function.

<u>Step-by-step explanation:</u>

We are given the relation as:

x: 0 , 2 , 4 , 6

y: -10 , -1 , 4 , 8

<em>Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).</em>

Hence, the corresponding relation is a function.

Now we have to find whether the inverse of this relation is a function or not.

When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.

Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.

Hence, Relation t is a function. The inverse of relation t is a function.

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3 years ago

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PLZZ HELP ME WILL GIVE BRAINLIEST ( write in exponential form) 26*26^8

Lisa [10]

Answer:

26 * 26^8 = 26^9

Step-by-step explanation:

Here, we want to write 26 * 26^8 in exponential form.

26* 26^8 is same as 26^1 * 26^8

According to the first law of indices, we are going to add the powers together;

Thus, this gives ; 26^(1 + 8) = 26^9

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3 years ago

Bret works for a printing company-each document takes 8 sheets of paper-he has 500 sheets-how many documents can he print

Juli2301 [7.4K]

Answer:

He can print 62 documents

Step-by-step explanation:

500/8=62.5

He can print only 62 documents because he cannot print half a document.

Hope this helps!

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2 years ago

Find the slope of the line drawn below

Marysya12 [62]

Answer:

slope is undefined

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (1, 2) and (x₂, y₂ ) = (1, - 3)

m = $\frac{-3-2}{1-1}$ = $\frac{-5}{0}$

Since division by zero is undefined then the slope of the line is undefined

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3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

so

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

so

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago