Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer: a) 0.84 b) 0.67 c) 1.28
Step-by-step explanation:
Using the standard normal distribution table for z-value , we have
(a) The value of would result in a 80% one-sided confidence interval :
(b) The value of would result in a 85% one-sided confidence interval :
(c) The value of would result in a 90% one-sided confidence interval :
Answer:
A. 18÷2/9
Step-by-step explanation:
A. 18÷2/9
B. 18×2/9
C. 2/9÷18
D. 9/2÷18
Let
Total length of box = 18 inches
Thickness of each book = 2/9 inches
Number of books that will fit into the box = x
Number of books that will fit into the box = Total length of box ÷ Thickness of each book
x = 18 ÷ 2/9
= 18 × 9/2
= 162/2
= 81 books
The correct answer is A. 18÷2/9
Answer:
g(x) > h(x) for x = -1.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).