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trasher [3.6K]
2 years ago
5

Need help, really not good with anything in math

Mathematics
1 answer:
Anettt [7]2 years ago
5 0

Answer:

  • D. 40.

Step-by-step explanation:

<u>Find the reciprocal of 1/40:</u>

  • 1/40
  • = 40/1
  • = 40.

<u>That's really it.</u>

Your answer is 40 (D).

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Need help please...answer correctly ​
Lelechka [254]

Answer:

9.09

Step-by-step explanation:

x=speed of boat

y=speed of water current

Downstream relative speed = x+y

Upstream relative speed = x-y

Distance remains the same for both upstream and downstream.

a) Distance travelled downstream = speed x time = 3(x+y)

Distance travelled upstream = speed x time = 3.6(x-y)

b) Since both distances are equal, we can write

3(x+y)= 3.6(x-y)

3x+3y = 3.6x-3.6y

6.6y = 0,6x

x=11y: y=x/11

c) Water current has speed as 1/11 times of that of boat

In percent this equals 100/11 = 9.09%

3 0
3 years ago
Read 2 more answers
I need help on my math hw please and thanks!!
jarptica [38.1K]
Attached solutions and work.

3 0
3 years ago
Radius: 3.5 units, Center (0,3.5)
vlabodo [156]

Step-by-step explanation:

General equation of circle:

(x - a)² + (y - b)² = r².

Therefore we have x² + (y - 3.5)² = 12.25.

5 0
2 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
2 years ago
Use the distributive property to find the product.
VladimirAG [237]

A Is your answer :D        

W^2 + 2W + 3

4 0
3 years ago
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