Answer:
-30 (2w + 3) is the only one I can figure out.
I hope this helped tho!! :]
To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,

Therefore, 500 gallons of 80% antifreeze solution is required.
0 , -6
6 , -12
4 , -10
-3 , -3
These are the ones i could think of now
Answer:
true.
Step-by-step explanation:
hope this helps, i looked it up :)