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Nina [5.8K]
3 years ago
5

An airplane starts at 0 feet. It rose 21,000 feet at takeoff. it then descended 4,329 feet because of clouds. An oncoming plane

was approaching, so it rose 6,333 feet. After the oncoming plane passed, it descended 8,453 feet, at what altitude was the plane flying?
SAT
1 answer:
sveta [45]3 years ago
3 0

answer

1). Airplane is flying at 14551 feet.

2). Height of the mountain is 4299 feet.

--------------------------------------------------------------------------------------------------------------

1). An airplane starts at the level = 0 feet

It rose to the altitude = 21000 feet

It descends by the height due to clouds = 4329 feet

So the height of the airplane = 21000 - 4329

= 16671 feet

After giving pass to a plane it ascends by the height = 6333 feet

Now the height of the airplane = 16671 + 6333

= 23004 feet

Then the airplane descends again to give the pass to a airplane again.

Altitude after descending by 8453 feet = 23004 - 8453 = 14551 feet

Airplane is flying at 14551 feet.

2). Distance between the top of the mountain to the floor of the valley = 4392 feet

Valley is 93 feet below the sea level.

Therefore, the height of the mountain will be = 4392 - 93

= 4299 feet

hope this helps you

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