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alexandr402 [8]
2 years ago
6

A student runs 100 meters in 11 seconds. What is the speed of the student? Speed= distance/time; 1 mile=1609

Mathematics
1 answer:
Mrrafil [7]2 years ago
8 0

Answer:

Speed=distance/time

100/11=9.1 m/s

1. 9.1 miles per hour

9.1 miles=14641.9 meters

1 hour= 60s

14641.9/60= 244.0 m/s

2. 16 miles per hour

16 miles= 25744 meters

25744/60= 429.1 m/s

3. 20.3 miles per hour

20.3 miles= 32662.7 meters

32662.7/60= 544.4 m/s

4. 24 miles per hour

24 miles= 38616 meters

38616/60= 643.6 m/s

* Note: Answers were rounded to the nearest tenth.

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a 15-foot telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 degre
scoundrel [369]

Answer:

The length of the wire is 22.42 feet

The distance from the base of the pole to the spot where the wire touches the ground is 16.66 feet

Step-by-step explanation:

* Lets explain the situation in the problem

- The telephone pole , the wire and the ground formed a right triangle

- The wire is the hypotenuse of the triangle

- The height of the telephone pole and the distance from the base of

 the pole to the spot where the wire touches the ground are the legs

 of the triangle

- The angle between the wire and the ground is 42°

- The angle 42° is opposite to the height of the telephone pole

- The height of the telephone pole is 15 feet

* Lets use the trigonometry functions to find the length of the wire

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∵ sin Ф = opposite/hypotenuse

∵ Ф = 42° and its opposite side = 15 feet

∴ sin 42 = 15/hypotenuse ⇒ by using cross multiplication

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∴ hypotenuse = 15/sin 42° = 22.42 feet

∵ The length of the wire is the hypotenuse

∴ The length of the wire is 22.42 feet

∵ The distance from the base of the pole to the spot where the wire

   touches the ground is the adjacent side to the angle 42°

∵ tan Ф = opposite/adjacent

∴ tan 42° = 15/adjacent ⇒ by using cross multiplication

∴ tan 42° (adjacent) = 15 ⇒ divide both sides by sin 42

∴ adjacent = 15/tan 42° = 16.66 feet

∵ The adjacent side is the distance from the base of the pole to the

  spot where the wire touches the ground

∴ The distance from the base of the pole to the spot where the wire

   touches the ground is 16.66 feet

7 0
3 years ago
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