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2 years ago

A student runs 100 meters in 11 seconds. What is the speed of the student? Speed= distance/time; 1 mile=1609

Mathematics

1 answer:

Mrrafil [7]2 years ago

8 0

Answer:

Speed=distance/time

100/11=9.1 m/s

1. 9.1 miles per hour

9.1 miles=14641.9 meters

1 hour= 60s

14641.9/60= 244.0 m/s

2. 16 miles per hour

16 miles= 25744 meters

25744/60= 429.1 m/s

3. 20.3 miles per hour

20.3 miles= 32662.7 meters

32662.7/60= 544.4 m/s

4. 24 miles per hour

24 miles= 38616 meters

38616/60= 643.6 m/s

* Note: Answers were rounded to the nearest tenth.

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Find the area. Please help im begging! ( Multiple choice )

Stels [109]

Answer:

B) 700.6
A) 440

Step-by-step explanation:

Use formula:

A = 1/2 Pa, where P-perimeter of the polygon, a- apothem

A = 1/2(7*13.9)(14.4) = 700.56 ≈ 700.6

Correct choice is B

A = 1/2(5*16)(11) = 440

Correct choice is A

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3 years ago

What is the estimated product of 908*67

professor190 [17]

Do 910*70 = 63700 The actual answer is 60,836 so it is pretty close

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3 years ago

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A falling object travels a distance given by the formula d=3t+5t2, where d is measured in feet and t is measured in seconds. How

Romashka-Z-Leto [24]

Answer:

4.52secs

Step-by-step explanation:

Given the height of a falling object expressed as;

d=3t+5t^2

If the object travel 84 feet, we are to find the time t it takes to travel. On substituting;

84 = 3t+5t^2

3t+5t^2 - 84 = 0

t = -5±√25-4(3)(-84)/2(3)

t = -5±√25+1008/6

t = -5±32.14/6

t = -5+32.14/6

t = 27.14/6

t = 4.52 secs

Hence it will take 4.52secs for the object to travel 84feet

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2 years ago

Answer this equation: 4 3/5 - -3 2/5 + 3

horrorfan [7]

Answer:

Step-by-step explanation:

$4\frac{3}{5} -(-3\frac{2}{5})+3$

Negative and another negative makes a positive.

$4\frac{3}{5}+3\frac{2}{5}+3$

Add the fractions first.

$7\frac{5}{5}+3$

5/5 is equivalent to 1. 7 5/5 becomes 8.

$8+3$

Add the numbers.

$24$

I hope this helps!

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3 years ago

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Help algebra 2 please

kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

= x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

= x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

= -5x³ + 2x² + 7x - 5x² + 2x + 7

= - 5x³ + 2x² -5x² + 7x + 2x +7 {Combine like terms}

= -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

= x*(x² + 2x + 4) - 2*(x² + 2x + 4)

= x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

= x³ + 2x² + 4x -2x² -4x - 8

= x³ - 8

$2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}$

$1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}$

7 0

3 years ago