The quadratic formula is =(-b+-sqrt(b^2-4ac))/2a
as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
so let us calculate b^2-4ac for our given equation
x^2=4x-5 so let us write it in general form which is ax^2+bx+c=0
subtracting 4x from both sides
x^2-4x=-5
adding 5 to both sides
x^2-4x+5=0
a=1,b=-4,c=5
b^2-4ac=(-4)^2-4(1)(5)=16-20=-4
which means the equation has two imaginary soultions
Answer:
$12.25
i hope this helps
Step-by-step explanation:
5+2=7
1.75×7=12.25
Answer:
Step-by-step explanation:
It's given in this question,
m∠2 = 41°, m∠5 = 94° and m∠10 = 109°
Since, ∠2 ≅ ∠9 [Alternate interior angles]
m∠2 = m∠9 = 41°
m∠8 + m∠9 + m∠10 = 180° [Sum of angles at a point of a line]
m∠8 + 41 + 109 = 180
m∠8 = 180 - 150
m∠8 = 30°
Since, m∠2 + m∠7 + m∠8 = 180° [Sum of interior angles of a triangle]
41 + m∠7 + 30 = 180
m∠7 = 180 - 71
m∠7 = 109°
m∠6 + m∠7 = 180° [linear pair of angles]
m∠6 + 109 = 180
m∠6 = 180 - 109
= 71°
Since m∠5 + m∠4 = 180° [linear pair of angles]
m∠4 + 94 = 180
m∠4 = 180 - 94
m∠4 = 86°
Since, m∠4 + m∠3 + m∠9 = 180° [Sum of interior angles of a triangle]
86 + m∠3 + 41 = 180
m∠3 = 180 - 127
m∠3 = 53°
m∠1 + m∠2 + m∠3 = 180° [Angles on a point of a line]
m∠1 + 41 + 53 = 180
m∠1 = 180 - 94
m∠1 = 86°
