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Trava [24]
3 years ago
15

Based on the table, how much more money would a person with a bachelor's degree earn than a person with an associate's degree ov

er a 30 year career?
A) $16,000
B) $480,000
C) $1,095,000
D) $1,575,000

Mathematics
2 answers:
ratelena [41]3 years ago
4 0

Answer:

$ 1,575,000 because $52,500 is annual salary so in 30 years ..30× annual salary = earning of person over a 30 years

Aleksandr [31]3 years ago
4 0

Answer:

B) $480,000

Step-by-step explanation:

Annual salary of a person with associate's degree

= $36,500

Over a 30 year career the person would earn;

= 30 × 36500

= $10,95,000

Now, annual salary of a person with bachelor's degree = $52,500

Over a course of 30 years he would earn;

= 30 × 52500

= $15,75,000

Difference = $15,75,000 - $10,95,000 = $480,000

So the person with bachelor's degree would earn $480,000 more than a person with associate's degree.

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Step-by-step explanation:

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Which is an example of continuous data?
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Answer:

A) amount of snowfall in a blizzard  

Step-by-step explanation:

Both continuous and discrete data are quantitative.

The difference is that  

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The amount of snowfall in a blizzard is continuous data.  It can take any value such as 100.3 cm or 250.5 cm .

B) is wrong. The number of students who pass a math quiz is discrete data. You can't have half a student.

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3 years ago
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<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B12x-7%3D0%20%5C%5C" id="TexFormula1" title="2x^{2} +12x-7=0 \\" alt="2x^{2}
m_a_m_a [10]

Answer:

-2. 46

- 9.54

Step-by-step explanation:

  • 2x²+12x-7=0
  • 2x²+12x+18= 25
  • 2*(x²+6x+9)=25
  • 2*(x+6)²= 5²
  • x+6= 5√2/2 ⇒ x= 5√2/2 -6 ≈ -2. 46
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4 0
3 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

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Answer:

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Step-by-step explanation:

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