You can find it by integrating twice:
![\displaystyle\int v''(x)\,\mathrm dx=\int(-6x+2)\,\mathrm dx\iff v'(x)=-3x^2+2x+C_1](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%20v%27%27%28x%29%5C%2C%5Cmathrm%20dx%3D%5Cint%28-6x%2B2%29%5C%2C%5Cmathrm%20dx%5Ciff%20v%27%28x%29%3D-3x%5E2%2B2x%2BC_1)
![\displaystyle\int v'(x)\,\mathrm dx=\int(-3x^2+2x+C_1)\,\mathrm dx\iff v(x)=-x^3+x^2+C_1x+C_2](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%20v%27%28x%29%5C%2C%5Cmathrm%20dx%3D%5Cint%28-3x%5E2%2B2x%2BC_1%29%5C%2C%5Cmathrm%20dx%5Ciff%20v%28x%29%3D-x%5E3%2Bx%5E2%2BC_1x%2BC_2)
Given that
![v(0)=0](https://tex.z-dn.net/?f=v%280%29%3D0)
, you have
![0=-0^3+0^2+0C_1+C_2\implies C_2=0](https://tex.z-dn.net/?f=0%3D-0%5E3%2B0%5E2%2B0C_1%2BC_2%5Cimplies%20C_2%3D0)
and given
![v(1)=-1](https://tex.z-dn.net/?f=v%281%29%3D-1)
,
![-1=-1^3+1^2+C_1\implies C_1=-1](https://tex.z-dn.net/?f=-1%3D-1%5E3%2B1%5E2%2BC_1%5Cimplies%20C_1%3D-1)
Answer:
10 blocks
Step-by-step explanation:
Given
![First = 6\ blocks](https://tex.z-dn.net/?f=First%20%3D%206%5C%20blocks)
east
Required
Determine the shortest possible distance
To better explain my solution, I've added an attachment that illustrates her movement.
Using the attachment as a point of reference, the shortest distance is calculated by calculating the length of the hypotenuse using Pythagoras theorem.
So, we have:
![x^2 = 6^2 + 8^2](https://tex.z-dn.net/?f=x%5E2%20%3D%206%5E2%20%2B%208%5E2)
![x^2 = 36 + 64](https://tex.z-dn.net/?f=x%5E2%20%3D%2036%20%2B%2064)
![x^2 =100](https://tex.z-dn.net/?f=x%5E2%20%3D100)
Take positive square root of both sides
![x = \sqrt{ 100](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B%20100)
![x = 10](https://tex.z-dn.net/?f=x%20%3D%2010)
The correct answer is A because 5 divided by $1.50 gives you 30 cents! if you divide any of the number of goldfish by the price it gives you $.30. Please mark brainliest
Step-by-step explanation:
How many people do the intend to invite