Answer:
width = 5 ft
length = 9 ft
Step-by-step explanation:
Here, we want to get the length and width of the garden
length is 1 ft less than twice the width
if width = w
length = 2w-1
The product of the two is 45
so, we have it that;
w(2w-1) = 45
2w^2 - w = 45
2w^2 - w -45 = 0
2w^2 - 10w + 9w -45 = 0
2w(w-5) + 9(w-5) = 0
(2w + 9)(w-5) = 0
2w + 9 = 0
or w -5 = 0
w = 5 or-9/2
w cannot be negative, so we = 5
l = 2(5) -1 = 10 - 1 = 9 ft
Y=x-2
-2 is the y-intercept. the slope is 1. Plug in the info for the slope-intercept form which is y=mx+b
Answer:
Scrambled Eggs | 6 | 9 | 12 |
Hard Boiled Eggs | 2 | 4 | 6 |
Step-by-step explanation:
Scrambled Egg = Scrambled Egg + 3
Hard Boiled Egg = Hard Boiled Egg + 2
Answer:
Option D.
Step-by-step explanation:
It is given that a satellite is composed of 30 modular units. Each unit contains the same number of non-upgraded sensors.
Let x be the total number of upgraded sensors on the entire satellite.
The number of non-upgraded sensors on one unit is 1/5 the total number of upgraded sensors on the entire satellite.
Non-upgraded sensors on one unit = ![\frac{1}{5}x](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7Dx)
Non-upgraded sensors on 30 unit = ![30\times \frac{1}{5}x=6x](https://tex.z-dn.net/?f=30%5Ctimes%20%5Cfrac%7B1%7D%7B5%7Dx%3D6x)
Total number of sensors on the entire satellite is the sum of upgraded and non-upgraded sensors
![Total=x + 6x = 7x](https://tex.z-dn.net/?f=Total%3Dx%20%2B%206x%20%3D%207x)
We need to find the fraction of the sensors on the satellite have been upgraded.
![Fraction=\frac{\text{Upgraded sensors}}{\text{Total sensors}}](https://tex.z-dn.net/?f=Fraction%3D%5Cfrac%7B%5Ctext%7BUpgraded%20sensors%7D%7D%7B%5Ctext%7BTotal%20sensors%7D%7D)
![Fraction=\frac{x}{7x}](https://tex.z-dn.net/?f=Fraction%3D%5Cfrac%7Bx%7D%7B7x%7D)
![Fraction=\frac{1}{7}](https://tex.z-dn.net/?f=Fraction%3D%5Cfrac%7B1%7D%7B7%7D)
Therefore, the correct option is D.