Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
~ 12.57
Step-by-step explanation:
Answer:
10 ft.
Step-by-step explanation:
8.8 ÷ 4= 2.2
22÷2.2= 10
Answer:
1) C) sin(θ) = 119/169
2) D) cos(θ) = 120/169
Step-by-step explanation:
The mnemonic SOH CAH TOA expresses the relationships you need for answering these questions.
Sin(θ) = Opposite/Hypotenuse = 119/169 . . . . . problem 1
Cos(θ) = Adjacent/Hypotenuse = 120/169 . . . . problem 2
Length of the diameter = sqrt ( (-12- (-8)^2) +(2-0)^2) )
= sqrt (16 + 4) = sqrt20
so radius = sqrt 20 / 2 = sqrt5
so r^2 = 5
Center of the circle = coordinates of the midpoint of the diameter =
-8-12/2 , 2-0 / 2 = (-10, 1)
(x - a)^2 + (y - b)^2 = r^2 is general form of a circle so here the circle is:_
(x + 10)^2 + (y - 1)^2 = 5 Answer
Its B
