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4 years ago

PLEASE ANSWER THE QUESTIONS IN THE PICTURE!!

Mathematics

1 answer:

Katen [24]4 years ago

6 0

Answer:

Step-by-step explanation:

The answer is c i got it corect because the widht is longer then bottom

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-3a + 4 ≥ -16<br><br> Solve, and show your work.

storchak [24]

Answer:

a ≤ 20/3

Step-by-step explanation:

Subtract 4 from both sides, obtaining:

-3a ≥ -20. Dividing both sides by -3, we get a ≤ 20/3.

Note that because this is an inequality, and because we've divided all terms by a negative number, we must change the direction of the inequality symbol from ≥ to ≤.

8 0

3 years ago

Read 2 more answers

Please I need help.<br>

soldi70 [24.7K]

Answer: A

Step-by-step explanation: if not A then B if not B then C if not C then D if not D then your teacher doesn't like you.

8 0

3 years ago

kaitlin is on a long car trip every time she stops she loses 15 minutes of travel time is she stops 5 times how late will she be

yanalaym [24]

5(15)= 75 minutes or an hour and 15 minutes lost

8 0

4 years ago

Read 2 more answers

16. PHYSICS The formula h = 1201 - 16t2 gives the height h in feet of an object 1 seconds after it is shot upward from

Murrr4er [49]

<h3><u>Question:</u></h3>

The formula h = 120t-16t^2 gives the height h in feet of an object t seconds after it is shot upward from Earth's surface with an initial velocity of 120 feet per second. What will the height of the object be after 6 seconds?

<h3><u>Answer:</u></h3>

The height of object after 6 seconds is 144 feet

<h3><u>Solution:</u></h3>

<em><u>The formula that gives the height of an object is:</u></em>

$h = 120t - 16t^2$

Where,

h is the height in feet and t is the time in seconds

To find: height of the object be after 6 seconds

To find the height of the object be after 6 seconds, substitute t = 6

$h = 120 \times 6 -16(6)^2\\\\h = 720 - 16 \times 36\\\\h = 720 - 576\\\\h = 144$

Thus height of object after 6 seconds is 144 feet

3 0

3 years ago

Two towns are 1,100 miles apart. A group of hikers Starts from each town and walks down the trail toward each other. They meet a

OLga [1]

Answer:

3.54 and 1.04

Step-by-step explanation:

Given:

Two towns are 1,100 miles apart.

A group of hikers Starts from each town and walks down the trail toward each other..

They meet after a total hiking time of 240 hours.

If one group travels 2 1/2 mile per hour slower than the other group.

<u>Question asked:</u>

Find the rate of each group.

<u>Solution:</u>

Let speed of faster hiker = $x\ mph$

Speed of slower hiker = $x-\frac{5}{2}\ mph$

<u /> $Distance=speed\times time$

Total distance between two town = Total combined speed of both hikers $\times$ Total combined time taken

$1100=(x+x-\frac{5}{2} )\times240\\ \\ Dividing\ both\ sides\ by\ 240\\ \\ 4.58=(x+x-\frac{5}{2} )\\ \\ 4.58=2x-\frac{5}{2} \\ \\Adding\ both\ sides\ by\ \frac{5}{2} \\ \\ 4.58+ \frac{5}{2}=2x- \frac{5}{2}+ \frac{5}{2}\\ \\ \frac{2\times4.58+5}{2} =2x\\ \\ \frac{14.16}{2} =2x\\ \\ By \ cross\ multiplication\\ \\ 2\times2x=14.16\\ \\ 4x=14.16$

$By\ dividing\ both\ sides\ by \ 4\\ \\ x=3.54\ miles\ per\ hour$

Speed of faster hiker = $x\ mph$ = 3.54 miles per hour.

Speed of slower hiker = $x-\frac{5}{2}\ mph$ =

$3.54-\frac{5}{2} =3.54-2.5=1.04\ miles\ per\ hour$

Therefore, speed of faster hiker is 3.54 miles per hour and speed of slower hiker is 1.04 miles per hour.

8 0

3 years ago