A cylindrical pipe is 25 ft long and has a volume of 900ft3 find it's approximate diameter to the nearest hundredth of a foot
1 answer:
Answer:
Diameter of the pipe ≈ 6.77 ft
Step-by-step explanation:
Volume of a cylinder = πr²h
Here, r = Radius of the cylindrical pipe
h = Length of the pipe
Volume of the pipe = 900 ft³
Length of the pipe = 25 ft
By substituting the given values in the formula,
900 = π(r)²(25)
r² =
r = √11.459
r = 3.385
Diameter = 2(radius)
= 2(3.385)
= 6.77 ft
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Answer:
Step-by-step explanation:
We can use the definition of inverse functions. Recall that if two functions, <em>f</em> and <em>g</em> are inverses, then:
So, we can let <em>j</em> be the inverse function of <em>h</em>.
Function <em>h</em> is given by:
Find its inverse. Flip variables:
Solve for <em>y. </em>Add:
Hence:
Therefore, <em>a</em> = 1/3 and <em>b</em> = 2/3.
We can verify our solution:
And:
ANSWER
72 square feet
EXPLANATION
The perimeter of a rectangle is given by:
P= 2l+2w
It was given that, the perimeter of the rectangular mat, is 36 feet.
36= 2l+2w
Divide through by 2.
It was given also that, the length of the mat is twice its width.
This implies that,
Put equation (2) into equation (1) to get,
This means that the length is 12 ft.
The area of the rectangular mat is
72 square feet
EXPLANATION
The perimeter of a rectangle is given by:
P= 2l+2w
It was given that, the perimeter of the rectangular mat, is 36 feet.
36= 2l+2w
Divide through by 2.
It was given also that, the length of the mat is twice its width.
This implies that,
Put equation (2) into equation (1) to get,
This means that the length is 12 ft.
The area of the rectangular mat is