Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer
we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0
using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3
the answer is
the first odd integer x is 1
the second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5
The GCF of 6^3, -9^2, and 12x is 3x, so you could rewrite it as
3x(2x^2-3x+4), hope this helps!
Answer:
The answer is 3.
Explanation:
Factors of 18:
1, 2, 3, 6, 9, 18.
Factors of 21:
1, 3, 7.
The highest number that both sets contain is 3, so the GCF will be 3.