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Mars2501 [29]
4 years ago
10

A shop has 8 different types of postcards and at least 13 of each type. how many selections of 12 postcards are there if

Mathematics
1 answer:
Zolol [24]4 years ago
4 0

Answer:

Answered

Step-by-step explanation:

It is a combbinatorics problem. let's think as we need to do 8 partitions  

of these 13 to separate the postcards of different types. So The number of

partitions of n=13 into r=8 terms counting 0's as terms as  C(n+r-1,r-1)​.

(a)

Here n=13 and r=8, put it in the above formula so we get C(13+8-1,8-1)= C(20,7)= 77520 selections.

b).

Here, either (i) we can choose none of type I or (ii) we choose one of type I

Case(i): r=7, n=12 (Here we have only 7 types to choose from​)

Case(ii): r=7, n=11 (Here we have only 11 cards to choose and only 7 types to choose them from)​

Case (i) + Case(ii) = ,C(12+7-1,7-1) + C(11+7-1,7-1) = C(18,6) + (17,6) = 18564+12376 = 30940 selections.

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In a department store a desk costs £120. In a sale the price in reduced by 10%. How much is the desk reduced by
goldfiish [28.3K]

Answer:

£12

Step-by-step explanation:

£120 ×10/100

= £12.

That is the answer. Good luck

5 0
3 years ago
Jonathan took 33 pictures on the class trip and 67
Semenov [28]

Answer:

<em>JONATHAN WILL NEED 14 PAGES.</em>

Explanation:

<em>33 + 67 = 100</em>

<em>100 - 12 = 88</em>

<em>88 ÷ 6 = 14.6666667 </em>

<em>14.6666667 ⇒ </em><u><em>14</em></u>

<em>(Round 14.6666667 down to 14 because Johnathan does not have .6666667 of a page.)</em>

<em></em>

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3 years ago
Solve for a.Question is in picture. Giving brainliest
levacccp [35]
A=3.6

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6 0
3 years ago
Mario was making cookies. He mixed 2½ cups of flour, 1¼ cups of sugar and ½ cup of brown sugar together in a bowl. How many cups
STatiana [176]

Answer:

4 1/4

Step-by-step explanation:

2 1/2 + 1 1/4 + 1/2 = 5/2 + 5/4 + 1/2

LCM = 4

5/2 x 2/2 = 10/4

5/4 = 5/4

1/2 x 2/2 = 2/4

10/4 + 5/4 + 2/4 = 17/4

                          = 4 1/4

Therefore he put 4 1/4 cups altogether.

7 0
3 years ago
Please help me as soon as posable!! In hurry!!(24 points)
attashe74 [19]

The sequence is geometric, so

a_n = r a_{n-1}

for some constant r. From this rule, it follows that

a_3 = r a_2 \implies 20 = 2r \implies r = 10

and we can determine the first term to be

a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15

Now, by substitution we have

a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots

and so on down to (D)

a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15

(notice how the exponent on r and the subscript on a add up to n)

4 0
2 years ago
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