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Xelga [282]
2 years ago
8

I will mark you brainiest if you can answer this

Mathematics
1 answer:
Vika [28.1K]2 years ago
7 0

Answer:

D

Step-by-step explanation:

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4(c-3)=8<br> what does c equals?<br> correct answers ONLY please
rodikova [14]
Is there like a picture or something?
5 0
3 years ago
Read 2 more answers
Three landmarks of baseballachievement are Ty Cobb’s batting average of 0.420 in 1911,Ted Williams’s 0.406 in 1941, and George B
harina [27]

Answer:

Ted Williams has the highest standardized score, hence Williams is the best of the three

Cobb is the second highest and hence, the better player

George Brett is third

Step-by-step explanation:

Given the data:

Decade : 1910 __ 1940 ____ 1970

Mean, μ: 0.266 __0.267 ___ 0.261

S/dev, σ : 0.0371 _ 0.0326 __ 0.0317

To compute the standard unit for batting averages, we obtain the standardized score for each of Cobb,Williams, and Brett.

Standardized score (Zscore) : (x - μ) / σ

Cobb, x = 0.420

Ted Williams, x = 0.406

George Brett, x = 0.390

COBB:

Zscore = (0.420 - 0.266) / 0.0371 = 4.1509

Ted Williams :

Zscore = (0.406 - 0.267) / 0.0326 = 4.2638

George, Brett = (0.390 - 0.261) / 0.0317 = 4.0694

Ted Williams has the highest standardized score, hence Williams is the best of the three

Cobb is the second highest and hence, the better player

George Brett is third

6 0
2 years ago
Pls please help me ASAP!!!
oksian1 [2.3K]

Answer:

z = 0

Step-by-step explanation:

3 (z + 7) = 21

3z + 21 = 21

3z = 0

z = 0

8 0
2 years ago
Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap
inna [77]

Solution:

Given: zj = 3- j2, zz = - 4 + j3

Part a:

zj = 3- j2 = 3.6e^{-j33.7^{\circ}}

zz = - 4 + j3 = 5e^{j143.1^{\circ}}

Part b:

|zj| = |3− j2| =  √3² +(−2)² = √13 = 3.60

|z1| =  √(3− j2)(3+ j2) = √ 13 = 3.60.

Part c:

With the help of part a:

z1z2 = 3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}

6 0
3 years ago
When QS=6x and CS=5x-8, what is AB?
patriot [66]

Answer:

AB = x+ 8

Step-by-step explanation:

Given : QS=6x and CS=5x-8

From the given figure,

QS = QC + CS

We are given with  QS  and CS

Replace it the above equation

6x = QC + 5x -8

Solve for QC

Subtract 5x on both sides

x = QC + -8

Add 8 on both sodes

QC= x + 8

QABC is a rectangle

QC = AB

So AB = x+ 8


4 0
3 years ago
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