Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°, 
⊥ 
, AP = 9, and PM = 16
² + 
² = ²
= 
+ PM = 9 + 16 = 25
= 25
² = ² + ² = 9² + ²
∴ ² = 9² + ²
Similarly we get;
² = 16² + ²
Therefore, we get;
² + ² = 9² + ² + 16² + ² = ² = 25²
2·² = 25² - (9² + 16²) = 288
² = 288/2 = 144
= √144 = 12
From ² = 9² + ², we get
= √(9² + 12²) = 15
= 15
From, ² = 16² + ², we get;
= √(16² + 12²) = 20
= 20.
Remark
First of all, you should notice that the number you want must end in 5 to get a remainder of 5. That's because your divisors all end in 0.
Step One
Factor the 3 divisors
40: 2 * 2 * 2 * 5
50: 2 * 5 * 5
60: 2 * 2 * 3 * 5
Step Two
Using these factors, find the LCM
There are 3 twos, 1 Three, and 2 fives.
The LCM is 8*3*25 = 600
Step Three
Find the first number over 1000 that is divisible by 600. That should be 1200 which is 600 * 2
So the answer to your question is 1205
There are 21 friends on the camping trip. Or 21 2/3.
Hope this helped!
