3 geometry questions, 30 points!
2 answers:
Answer:
A ) The value of x for the given circle with chords and center is 8.3
B) The circumference of circle with chords 1.2 cm and 0.5 cm is 4.082
Step-by-step explanation:
Given two figures :
<u>For Figure first </u>
A circle with center y , having two chords FM and NM
FM = 5 x
MN = 2 x + 25
Now from theorem of circle ,
Chords equidistant from center of circle are equal in length
I.e distance of chord MN from center y and distance of FM from center y are equal
So, FM = MN
Or, 5 x = 2 x + 25
Or, 5 x - 2 x = 25
Or, 3 x = 25
∴ x = = 8.33
<u>For figure second</u>
The length of two adjacent chords of circle is 1.2 cm and 0.5 cm
Let the center of circle = O
Length of chord AB = 1.2 cm
Length of chord BC = 0.5 cm
As both chords are at 90° to each other
So The Length of diameter of circle AC =
Or, The Length of diameter of circle AC =
Or, The Length of diameter of circle AC =
Or, The Length of diameter of circle AC =
∴ The Length of diameter of circle AC = 1.3 cm
So, Circumference of circle =
Or, Circumference of circle = 3.14 × 1.3
∴ Circumference of circle = 4.082 cm
Hence,
A ) The value of x for the given circle with chords and center is 8.3
B) The circumference of circle with chords 1.2 cm and 0.5 cm is 4.082 Answer
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Answer:
The 3 numbers are 9, 12, and 15.
Step-by-step explanation:
I will answer in English, below the answer you can see a translation in Catalan.
This can be translated to:
The sum of the squares of three consecutive and multiple natural numbers of 3 is equal to 450. Pose a quadratic equation and calculate the three numbers.
First, a multiple of 3 can be written as:
3*n
The consecutive multiple of 3 is:
3*n + 3
The consecutive multiple of 3 is:
3*n + 3 + 3
Then the sum of their squares is:
(3*n)^2 + (3*n + 3)^2 + (3*n + 6)^2
And we know that this is equal to 450, then we need to solve the equation:
(3*n)^2 + (3*n + 3)^2 + (3*n + 6)^2 = 450
let's solve this:
9*n^2 + (9*n^2 + 2*(3*n)*3 + 9) + (9*n^2 + 2*(3*n)*6 + 36) = 450
27*n^2 + 54*n + 45 = 450
we can write this as:
27*n^2 + 54*n + 45 - 450 = 0
27*n^2 + 54*n - 405 = 0
The solutions of this equation are given by the Bhaskara's formula, and the solutions are:
we know that our numbers are naturals, then the numbers are positives, which means that we only care for the positive solution of n, which is:
n = (-54 + 216)/54 = 3
Then the 3 numbers are:
3*n = 3*3 = 9
(3*n + 3) = (3*3 + 3) = 12
(3*n + 6) = (3*3 + 6) = 15
In Catalan:
En primer lloc, es pot escriure un múltiple de 3 com:
3 * n
El múltiple consecutiu de 3 és:
3 * n + 3
El múltiple consecutiu de 3 és:
3 * n + 3 + 3
Llavors, la suma dels seus quadrats és:
(3 * n) ^ 2 + (3 * n + 3) ^ 2 + (3 * n + 6) ^ 2
I sabem que això és igual a 450, llavors hem de resoldre l’equació:
(3 * n) ^ 2 + (3 * n + 3) ^ 2 + (3 * n + 6) ^ 2 = 450
resolem això:
9 * n ^ 2 + (9 * n ^ 2 + 2 * (3 * n) * 3 + 9) + (9 * n ^ 2 + 2 * (3 * n) * 6 + 36) = 450
27 * n ^ 2 + 54 * n + 45 = 450
podem escriure això com:
27 * n ^ 2 + 54 * n + 45 - 450 = 0
27 * n ^ 2 + 54 * n - 405 = 0
Les solucions d’aquesta equació vénen donades per la fórmula de Bhaskara, i les solucions són:
sabem que els nostres nombres són naturals, aleshores els nombres són positius, cosa que significa que només ens importa la solució positiva de n, que és:
n = (-54 + 216) / 54 = 3
Llavors els 3 nombres són:
3 * n = 3 * 3 = 9
(3 * n + 3) = (3 * 3 + 3) = 12
(3 * n + 6) = (3 * 3 + 6) = 15