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Luden [163]
4 years ago
6

40.) Decompose 7/8 into the sum of unit fractions.​

Mathematics
1 answer:
Paraphin [41]4 years ago
4 0

Answer:

7/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8

7/8 = 1/8 + 6/8

7/8 = 4/8 + 3/8

7/8 = 5/8 + 2/8

Step-by-step explanation:

Hope it helps!

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65 degrees. alternate exterior angles of two parallel lines intersected by a transversal are equal

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7th grade math help me please :))
KatRina [158]

Answer:

40

Step-by-step explanation:

s = 2;

h = 4

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7 0
3 years ago
Suppose that the speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles p
denis23 [38]

Answer:

A)X \sim N(68 , 25)

B) the probability that is traveling more than 70 mph is 0.3446

C) the probability that it is traveling between 65 and 75 mph is 0.6449

D) 90% of all cars travel at least 56.85 mph fast on the freeway

Step-by-step explanation:

The speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles per hour.

Mean = \mu = 68 mph

Standard deviation = \sigma = 5 mph

A) X ~ N( _____, _______ )

In general X \sim N( \mu , \sigma^2)

\mu = 68 mph

\sigma = 5 mph

\sigma^2 = 5^2 = 25

So, X \sim N(68 , 25)

B) If one car is randomly chosen, find the probability that is traveling more than 70 mph.i.e.P(X>70)

So,Z = \frac{x-\mu}{\sigma}\\Z=\frac{70-68}{5}

Z=0.4

Using Z table

P(Z>70)=1-P(Z<70)=1-0.6554=0.3446

Hence the probability that is traveling more than 70 mph is 0.3446

C) If one of the cars is randomly chosen, find the probability that it is traveling between 65 and 75 mph.

P(65<X<75)

Z = \frac{x-\mu}{\sigma}

AT x = 65

Z=\frac{65-68}{5}

Z=-0.6

AT x = 75

Z=\frac{75-68}{5}

Z=1.4

Using Z table

P(65<X<75)=P(-0.6<Z<1.4)=P(Z<1.4)-P(Z<-0.6)=0.9192-0.2743=0.6449

Hence the probability that it is traveling between 65 and 75 mph is 0.6449

D)90% of all cars travel at least how fast on the freeway?

Since we are supposed to find at least how fast on the freeway

So,P(X>x)=0.9

1-P(X<x)=0.9

1-0.9=P(X<x)

0.1=P(X<x)

Z value at 10% =-2.23

So, Z=\frac{x-\mu}{\sigma}\\-2.23=\frac{x-68}{5}\\-2.23 \times 5 =x-68\\(-2.23 \times 5)+68=x

56.85 = x

Hence 90% of all cars travel at least 56.85 mph fast on the freeway

8 0
3 years ago
Jose sold 154 chocolate bors. Allie
Eduardwww [97]

Answer:

154*3-197 or 265

Step-by-step explanation:

154*3 = 462, 462-197=265.

4 0
3 years ago
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