Answer:
x = 3.4
Step-by-step explanation:
recall that for a right angle with an internal angle θ,
cos θ = adjacent length / hypotenuse
in our case,
θ = 55 deg
adjacent length = x units
hypotenuse = 6 units
substitute these into the formula above
cos θ = adjacent length / hypotenuse
cos 55 = x / 6 (multiply both sides by 6)
x = 6 cos 55 (use calculator)
x = 3.4415
x = 3.4 (rounded to nearest tenth)
You can plug 0 into y for the x intercept and 0 into x for the y intercept.
Answer:
SEE BELOW IN BOLD.
Step-by-step explanation:
a.
h = -16t^2 + 50t
h = 20 t
When the height is the same:
-16t^2 + 50t = 20t
-16t^2 + 30t = 0
t(-16t + 30) = 0
t = 0 or -16t + 30 = 0, so:
t = 0 or -30/-16 = 1.875
So the answer is 1.88 seconds to the nearest hundredth.
b.
For the ball
h = -16t^2 + 50t
Finding the derivative and equating to zero:
dh/dt = -32t + 50 = 0
t = -50/-32 = 1.563
Maximum height after 1.56 seconds to nearest hundredth
c.
When the ball hits the ground h = 0 so
-16t^2 + 50t = 0
-16t(t - 50/16)= 0
T = 3.13 SECONDS TO THE NEAREST HUNDERDTH
The answer is:
(v-1)(v+1)(v^2+1)
