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3 years ago

R + 3 1/2 = -4 2/3 what does r equal

1 answer:

6 0

$R+3\frac{1}{2}=-4\frac{2}{3}\ \ \ \ | subtract\ 3\frac{1}{2}\\\\
R=-4\frac{2}{3}-3\frac{1}{2}\ \ \ | make\ a\ common\ denominator\\\\
R=-4\frac{4}{6}-3\frac{3}{6}\\\\
R=-7\frac{7}{6}=-8\frac{1}{6}\\\\Solution:\ R=-8\frac{1}{6}$

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Two brothers, richard and andrew, share a sum £30 in the ratio 3:7. how much does each brother get?

Elina [12.6K]

Answer:

£9,£21

Step-by-step explanation:

richard:andrew=3:7

3+7=10

£30÷10=£3

richard=3×£3=£9

andrew=7×£3=£21

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3 years ago

Read 2 more answers

PLZ I WILL GIVE BRAILIEST TO THE FIRST ANSWER

natima [27]

Option B is the correct answer.

3 is greater than -5, -9, and -1.

Hint: Remember to distribute the negative when solving. A negative directly outside outside of and to the left the parenthesis times a negative number inside the parenthesis makes that number positive.

So for option B, you can simplify it to -3 +4 +2. And that equals 3.

A) -3+-4-(-2) = -5

B) -3-(-4)-(-2) = 3

C) -3+(-4)-2 = -9

D) -3-(-4)-2 = -1

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3 years ago

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Solve for x help ASAP

puteri [66]

Answer: x=6 and the angle is 50

Step-by-step explanation:

1. a whole triangle = 180°

2. subtract 70 and 60 to get 50

3. subtract 2 from 50 and get 48

4. divide 48 by 8 and you get 6.

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3 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .