Answer: 45 miles
Step-by-step explanation:
1 inch = 15 miles. Because there are 3 inches we will need to multiply by 3. 3 x 15= 45
Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


Answer:
<h2>90</h2>
Step-by-step explanation:
Substitute a = -3 and b = -8 to the expression 10a²b⁰:
10(-3)²(-8)⁰ = 10(9)(1) = 90
a⁰ = 1 for any real number
Answer:
25%
Step-by-step explanation:
.25(3,600)=900
3,600+900=4,500
Answer:
-42.66666...
Step-by-step explanation:
-64 * 2/3 is -42.66666...
well, according to the calculator.