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katen-ka-za [31]
3 years ago
8

Complete the identity, sin(a+b)/cosacosb=​

Mathematics
1 answer:
8090 [49]3 years ago
5 0

Answer:

tana + tanb

Step-by-step explanation:

Using the trigonometric identities

• sin(a + b) = sinacosb + cosasinb

• tanx = \frac{sinx}{cosx}, then

\frac{sin(a+b)}{cosacosb}

= \frac{sinacosb+cosasinb}{cosacosb}

= \frac{sinacosb}{cosacosb} + \frac{cosasinb}{cosacosb}

= \frac{sina}{cosa} + \frac{sinb}{cosb}

= tana + tanb

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Explain how you know 7(2 - 3n) and (2 - 3n) x 7 are equivalent expressions.​
iogann1982 [59]

Answer:

When you distribute the 7 to each set you get 14-21n and 14-21n

Step-by-step explanation:

5 0
3 years ago
If a+b=5 and a-b=4 then b^2-a^2 =
Anna007 [38]

Answer:

a + b = 5 \\ a \:  = 5 - b \\  a - b = 4 \\ 5 - b - b = 4 \\ 5 - 2b = 4 \\ 5 - 4 = 2b \\ 1 = 2b \\  \frac{1}{2}  =  \frac{2b}{2}  \\0.5 = b \\  b = 0.5 \\ a = 5 - b \\  = 5 - 0.5 \\  = 4.5 \\  {a \: }^{2}  -  {b}^{2}  = ( {4.5}^{2})  - (  {0.5}^{2} )  \\  = 20.25 - 0.25 \\  = 20 \\  {a}^{2}  -  {b}^{2}  = 20

Step-by-step explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

5 0
3 years ago
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Alik [6]

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C

Step-by-step explanation:

7 0
3 years ago
Evaluate 2xsquared by 2 − 5y over 3x −y when x = 2 and y = -4.
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8 0
3 years ago
Write the equation of the circle with center (0, 6) and radius 1.
lions [1.4K]
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(x-h)^2 + (y-k)^2 = r^2

The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa. 

The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1. 

(x)^2 + (y-6)^2 = 1
4 0
3 years ago
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