1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flura [38]
3 years ago
10

What is the solution of −81=b6 ? A. b = −486 B. b = −75 C. b = 13.5 D. b = 486

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0
We have to isolate b to be alone. 
Soooo first we divide both sides by 6

-81 = b6
÷6  = ÷6  The right side cancels out and gets the b alone. While we solve the right side of the equal sign. 
-81 ÷ 6 = -13.5 
So this means we isolated b alone!
b = -13.5 

Our final answer is..
b = -13.5 

:)

You might be interested in
Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
6 0
3 years ago
Read 2 more answers
What are the coordinates of the midpoint between A(−3, −5) and B(2, 7) ?
natka813 [3]
Use X1+X2 / 2, Y1+Y2 / 2
-3 + 2 / 2 , -5 + 7 / 2
-1 / 2 , 2/2
(-1/2, 1)

I think this is correct... I know you use the top formula
4 0
3 years ago
A seal went 15 below sea level to catch a fish. A sea lion dove 6 feet less than two times as deep as the seal to catch a larger
anygoal [31]

Answer:

2\times 15-6 = 24\ below\ sea\ level

Step-by-step explanation:

Given that:

Distance traveled by seal to catch the fish = 15 below sea level

Sea lion wanted to catch a larger fish so sea lion dove 6 feet lesser than two time the distance that the seal traveled.

To find:

The expression to represent the position of the sea lion in the sea.

Solution:

If the distance traveled by seal is represented by D then as per the question statement:

Twice of D = 2\times D

6 lesser than twice of D = 2\times D - 6

Now, putting the value of D = 15

Therefore, the expression to represent the sea lion's position w.r.to sea level.

2\times 15-6\\ = 24\ below\ sea\ level

5 0
3 years ago
This is a easy question, but what is the easiest way you could solve for slope? <br> :) ty
Cloud [144]
Seeing where the x and y diffreant on the line :)
4 0
3 years ago
Read 2 more answers
Find the HCF of 126 and 420
melamori03 [73]

Answer:

42

Step-by-step explanation:

Find the prime factorization of 126

126 = 2 × 3 × 3 × 7

Find the prime factorization of 420

420 = 2 × 2 × 3 × 5 × 7

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 3 × 7

GCF = 42

3 0
3 years ago
Other questions:
  • Write this number in word form 45,920
    8·2 answers
  • Indeed help with this plz
    12·2 answers
  • Two thirds of a number, decreased by thirty six, is at most twenty two. Find the number.
    12·1 answer
  • HELP PLZZZZ
    9·1 answer
  • Help me solve this please
    10·1 answer
  • Solve the system using elimination 3x+2y=17 and 2x+5y=26
    13·1 answer
  • 100 points
    9·2 answers
  • In isosceles triangle FGH, FG is congruent to GH. If Elijah draws a line segment from the vertex G to the midpoint of FH, labeli
    6·2 answers
  • A quiz has 8 multiple choice questions and 4 options for each. How many ways are there to answer the questions
    5·2 answers
  • Help please!!!!!!<br> Will give brainliest
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!