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Flura [38]
3 years ago
10

What is the solution of −81=b6 ? A. b = −486 B. b = −75 C. b = 13.5 D. b = 486

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0
We have to isolate b to be alone. 
Soooo first we divide both sides by 6

-81 = b6
÷6  = ÷6  The right side cancels out and gets the b alone. While we solve the right side of the equal sign. 
-81 ÷ 6 = -13.5 
So this means we isolated b alone!
b = -13.5 

Our final answer is..
b = -13.5 

:)

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A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,
katovenus [111]

Answer:

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation  

X_{1}=45 represent the number of correct answers for university degree holders

X_{2}=57 represent the number of correct answers for university non-degree holders  

n_{1}=373 sample 1 selected

n_{2}=639 sample 2 selected

p_{1}=\frac{45}{373}=0.121 represent the proportion of correct answers for university degree holders  

p_{2}=\frac{57}{639}=0.0892 represent the proportion of correct answers for university non-degree holders  

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0
3 years ago
Any help will be great!
son4ous [18]

Answer:

180

Step-by-step explanation:

75% times 240 would be 180

6 0
3 years ago
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Which rule describes the translation?
max2010maxim [7]

Answer:

c

Step-by-step explanation:

translations assignment

4 0
3 years ago
Solving systems of equations using substitution p=q+3 4p+3q= -30
patriot [66]
4(q+3) + 3q = -30
4q +12 + 3q = -30
7q+12= -30
7q = -12-30
7q = -42
q = -6
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5 0
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Thirty 5 points for this answer. no links.<br> 4(a-2) = 2(a-4) + 2a
Anarel [89]

Answer:

a = 0

Step-by-step explanation:

4(a-2) = 2(a-4) + 2a

4a - 8 = 2a - 8 + 2a

4a - 2a - 2a = -8 + 8

    0             =    0

5 0
3 years ago
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