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3 years ago

9

PLEASE ANSWER ASAP !!!!! WILL GIVE BRAINLIEST

2 answers:

Elanso [62]3 years ago

8 0

Answer:

$\sqrt{\frac{3V}{\pi*h}} = r$

Step-by-step explanation:

$V = \frac{1}{3}\pi r^2h\\3V = \pi r^2h\\\frac{3V}{\pi*h} = r^2\\\sqrt{\frac{3V}{\pi*h}} = r$

PSYCHO15rus [73]3 years ago

5 0

Answer:

r = +/- $\sqrt{\frac{3v}{\pi h}\}$

Step-by-step explanation:

v = 1/3 pi r^2 h

multiply both sides by 3

3v = pi r^2 h

dived both sides by pi h

3v/pi h = r^2

take sqrt of both sides

+/- sqrt( 3v/pi h) = r

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How would I start to solve number 15? Would I use distributive property?

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3 years ago

1. The digit 7 is in what place in these numbers?<br> (a) 271<br> (b) 793<br> (c) 407

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3 years ago

Read 2 more answers

8. A rectangle's sides are measured to be 6.2 cm and 9.3 cm. What is the

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3 years ago

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago