All categories

3 years ago

PLEASE ANSWER ASAP !!!!! WILL GIVE BRAINLIEST

Mathematics

2 answers:

Elanso [62]3 years ago

8 0

Answer:

$\sqrt{\frac{3V}{\pi*h}} = r$

Step-by-step explanation:

$V = \frac{1}{3}\pi r^2h\\3V = \pi r^2h\\\frac{3V}{\pi*h} = r^2\\\sqrt{\frac{3V}{\pi*h}} = r$

PSYCHO15rus [73]3 years ago

5 0

Answer:

r = +/- $\sqrt{\frac{3v}{\pi h}\}$

Step-by-step explanation:

v = 1/3 pi r^2 h

multiply both sides by 3

3v = pi r^2 h

dived both sides by pi h

3v/pi h = r^2

take sqrt of both sides

+/- sqrt( 3v/pi h) = r

You might be interested in

The fraction part of a question with feet and inches

AleksandrR [38]

It can be or it depends on how the equation is set up

6 0

4 years ago

The crafting club sold art calendars for a recent fundraiser. The table below lists the number of calendars sold by each member

solniwko [45]

Answer:

there is no table below, you have to add a picture

Step-by-step explanation:

3 0

3 years ago

Which of the following points would be on the graph of the equation y=4x+6

o-na [289]

Some of the possible points using this equation are...
(2,14)
(1,10)
(0,6)
(-1,2)
(-2,-2)

5 0

3 years ago

You are going to play a game where you bet a dollar and get to flip a coin ten (10) times. If you get four (4) heads in a row, y

klio [65]

Answer:

Approximately 4,000 times

Step-by-step explanation:

If you're flipping a coin to get 4 heads out of 10 and you times it by 10,000 then you would have a probable win rate of 4,000.

3 0

4 years ago

Secant BE and CF intersect at point A inside D. What is the measure of BF?

svet-max [94.6K]

Answer:

$\text{BF}=80^{\circ}$

Step-by-step explanation:

We have been given a circle D. Secant BE and CF intersect at point A inside D. We are asked to find the measure of arc BF.

We know that when two secants intersect inside a circle, then the measure of angle formed is half the sum of intercepting arcs.

$m\angle EAF=\frac{\text{Measure of arc EF+Measure of arc BC}}{2}$

$70^{\circ}=\frac{\text{Measure of arc EF+Measure of arc BC}}{2}$

$2*70^{\circ}=\frac{\text{Measure of arc EF+Measure of arc BC}}{2}*2$

$140^{\circ}=\text{Measure of arc EF+Measure of arc BC}$

We know that degree measure of circumference of circle is 360 degrees, so we can set an equation as:

$\text{Arc EF+BC+EC+BF}=360^{\circ}$

$140^{\circ}+140^{\circ}+\text{BF}=360^{\circ}$

$280^{\circ}+\text{BF}=360^{\circ}$

$280^{\circ}-280^{\circ}+\text{BF}=360^{\circ}-280^{\circ}$

$\text{BF}=80^{\circ}$

Therefore, the measure of arc BF is 80 degrees.

5 0

3 years ago