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Fiesta28 [93]
3 years ago
9

There are 31 days in the month of may. what fraction of the month does 10 days represent

Mathematics
1 answer:
viktelen [127]3 years ago
5 0

Answer:

10/31

Step-by-step explanation:

I'm pretty certain this is the answer, since 10/31 cannot be simplified any further; 31 being the total days in the month of May

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If I feed my lizard every 3rd day, and I feed my snake every 7th day, then on what day would they both be fed?
dusya [7]

Answer:

21st `day

Step-by-step explanation:

3*3*3*3*3*3*3=21

7*7*7=21

21 is the lcm of 3 and 7

8 0
3 years ago
Please answer it in two minutes
ch4aika [34]

Answer:

67 in

Step-by-step explanation:

Because these are congruent figures, you know that the last remaining segment is 67in

3 0
3 years ago
What is the factor for 30n-40
nikitadnepr [17]
Factor: 
<span>30n - 40 = 10(3n - 4)

hope it helps</span>
7 0
3 years ago
Which expression is equivalent to 7/2h - 3 (5h - 1/2)
poizon [28]

7/2h-3/2step-by-step

explicacion: 7/2h-3=37/2h5h

1/2= 3/2Expression made:37/2h 3/2

5 0
3 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
2 years ago
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