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3 years ago

Write the standard equation of the circle with the given Center and radius:

Mathematics

1 answer:

Kipish [7]3 years ago

5 0

9514 1404 393

Answer:

B. (x +4)² +(y +5)² = 64

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

(x -h)² +(y -k)² = r²

Filling in your given values, you have ...

(x -(-4))² +(y -(-5))² = 8²

Simplifying, you get ...

(x +4)² +(y +5)² = 64 . . . . . . . matches choice B

_____

<em>Additional comment</em>

As you learn more different "standard form" equations, it may be helpful to keep a list, along with reminders of what the variables stand for and how the equation is used.

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Find the area of this prism.

RUDIKE [14]

Do you mean volume? Its a 3d figure:
240 cubic centimeters.

Just use the formula length x width x height
And divide the figure into two figures so u can find the area much easier

Comm.ent me if u have any questions,
-SpaceMarsh
Brainliest pls?

8 0

3 years ago

Find the area of the isoceles triagle (hight not given)

Igoryamba

Answer:

157

Step-by-step explanation:

TSA OF TRIANGLE IS 180

13+10 IS 23

180-23 IS 157

8 0

3 years ago

2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explai

nasty-shy [4]

Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

$\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}$

$\frac{1}{4} = \frac{15 + x + x}{x(15+x)}$

$\frac{1}{4} = \frac{15 + 2x}{x(15+x)}$

Applying cross multiplication.

$x^2 + 15x = 4(15 + 2x)$

$x^2 + 15x = 60 + 8x$

$x^2 + 7x - 60 = 0$

Quadratic equation with $a = 1, b = 7, c = -60$ . So

$\Delta = 7^{2} - 4*1*60 = 289$

$x_{1} = \frac{-7 + \sqrt{289}}{2} = 5$

$x_{2} = \frac{-7 - \sqrt{289}}{2} = -12$

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.

4 0

3 years ago

Plz help me on this quick

Studentka2010 [4]

Answer: The third one

Step-by-step explanation: We can eliminate the first one right off the bat sinc we see that -4 has two outputs. Next, the graph's equation has no slope (x=3) so the input is all the same. Thirdly, the table shows a relationship between x and y and the numbers don't have a pattern that shows more than one output or input for a number. The fourth option are simply coordinates, it doesn't particularly tell us that all the coordinates are related to each other.

7 0

3 years ago

In the parallelogram DEFG, DH=x+1, HF=3y, GH=3x-4, and HE=5y+1. Find the values of x and y. The diagram is not drawn to scale.

RideAnS [48]

Answer:

Step-by-step explanation:

Given: In parallelogram DEFG,

DH = x + 1

HF = 3y

GH = 3x - 4

and HE = 5y + 1

Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore

x+1=3y (1)

3x-4=5y+1 (2)

Multiply equation (1) with 3 and then subtract equation (2) from it, we get

3x+3-3x+4=9y-5y-1

7=4y-1

y=2

Substituting the value of y=2 in equation (1), we get

x+1=3(2)

x=5

Therefore, the value of x and y are 5 and 2 respectively.

8 0

4 years ago