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3 years ago

What transformations change the graph of (f)x to the graph of g(x)?. . f(x) = x² ; g(x) = (x + 7)² + 9 (1 point)

1 answer:

5 0

So base on your question what could be the change in the graph of f(x) to the graph of g(x) where f(x)=x^2 while g(x) =(x+7)^2 +9. So base to that fact the function g(x) is assigned to f(x) so it becomes f(gx) = ((x+7)^2+9)2 and i think the graph may be increase or decrease according to the value of X.

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3 years ago

Please help they are separate questions please help me with this!

monitta

Answer: Mary makes $1160, Steven makes $142.50

Step-by-step explanation:

Facts

MARY

8% commision on everything she sells

She sells a car for $14,500

The first question about Mary asks how much commision she makes. To find that, lets find 8% of 14,500

8% of 14,500= 0.08x14,500= 1160

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6 0

2 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

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3 years ago