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Softa [21]
3 years ago
10

The mean of 7 numbers is 6. What is the total of the numbers?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0
42. The mean is the total of the numbers divided by the amount of numbers. In this case the amount of numbers is 7 and the mean is 6. That means that the total of the numbers divided by 7 equals 6. To find the total you just do the opposite, multiply 7 by 6 and you get 42.
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Solve 4x-2y=6 for x in terms for y
Elina [12.6K]

Answer:

x = 3 + y

Step-by-step explanation:

4x - 2y = 6

~Add 2y to both sides

2x = 6 + 2y

~Divide 2 to everything

x = 3 + y

Best of Luck!

5 0
2 years ago
Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m > 1 so that th
jonny [76]

Answer:

The answer is \sqrt{\frac{6}{5}}

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy

Solving:

\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy

[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.

Replacing the limits:

6*\frac{1}{3} =2

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ \frac{1}{m}

Solving the double integral with these new limits we have:

\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy

This part is a little bit tricky so let's solve the integral first for dy:

\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx

Replacing the limits:

\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx

Solving now for dx:

[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.

Replacing the limits:

\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}

As I mentioned before, this volume is equal to 1, hence:

\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }

3 0
3 years ago
How do I solve these trigonometric functions?
aleksandr82 [10.1K]

Answer:

see attached

Step-by-step explanation:

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<span>450/100=x/145. Cross multiply to get 100x=65250. Divide by 100 to get 652.50. The selling price of the painting is $652.50. Brainlest?</span>
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3 years ago
10. A young child is 44 months old. Find the age of the baby in years as a mixed
viktelen [127]

Step-by-step explanation:

44 month old

12 months=1 year

44÷12=3 2/3

3 2/3 years

5 0
3 years ago
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