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romanna [79]
3 years ago
9

Pleas help I will mark brainliest

Mathematics
2 answers:
kramer3 years ago
3 0

The area for one side is S^2 where S is the length of one side.

The area for one side = 1/2^2 = 1/4 square foot.

A cube has 6 sides. Total surface are = 1/4 x 6 = 1 1/2 square feet.

Volume of a cube is S^3

1/4^3 = 1/64 cubic foot.

balu736 [363]3 years ago
3 0
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Please help me on this question
Masja [62]

Answer:

The number is 5

Step-by-step explanation:

Let x be the number

3x+5+x = 25

Combine like terms

4x+5 = 25

Subtract 5 from each side

4x+5-5 = 25-5

4x = 20

Divide by 4

4x/4 = 20/4

x = 5

8 0
4 years ago
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The quotient of -6 and y
Oxana [17]
Quotient of means divide (place division symbol where "and" is located)

-6 ÷ y  or \frac{-6}{y}
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3 years ago
Which expressions are equivalent?
Phoenix [80]

im pretty sure it's the first option.

6 0
3 years ago
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Need help ASAP no Rocky
Ahat [919]

Answer:

The length of mid-segment XY=4 units

Step-by-step explanation:

Given:

Length of QR=8 units

XY is the mid-segment which means the line joining the midpoints of two sides of triangle.

By mid-segment theorem the mid-segment of a triangle is parallel to the third side and half of the length of third side.

So, we can write:

XY=\frac{1}{2}QR  

XY=\frac{1}{2}(8)

∴ XY=4 units

∴The length of mid-segment XY=4 units

5 0
3 years ago
A standard oil drum is a cylinder with a volume of approximately 218.276 liters (or 0.218276 cubic meters). The cost of producin
Arte-miy333 [17]

Answer:

r = 2,85 feet

h = 8,56 feet

Step-by-step explanation:

Area of two circular caps (m ^(2)) : 2* pi* r^(2) (where  r is the radius of circular cap)     Area of wall (m ^(2))  is 2*pi*r*h (where h is the height of drum)

V= pi*r^(2)*h           so  h=V/pi*r^(2)   (1)

Cost in $:

Cost of wall 25 $/m^(2) plus 10% for manufacturing so:

C(w) = 27,5*2*pi*r*h $/square feet

Cost of (both top and bottom cap) = 2*40,97*pi* r^(2) so:

C(caps) = 257,29* r^(2) $/squaer feet

Total cost of cylnder = cost of wall + cost of caps

Total cost f cylinder: F(c)= 55*pi*r*h+257,29* r^(2)

F(c) = 172,7*r*h + 257,29*r^(2)         F(c)  is F(r)

Since from (1) we have h=218,276/pi*r^(2)  

F(r) = (172,7)*r*(69,514)/r^(2) +257,29*r^(2)           F(c) = 12005/r + 257,29*r^(2)

Taken the first dervative

F´(r)= -12005*(1)/r^(2) +2*257,29*r         F´(r) =  -12005*(1)/r^(2) +514,58*r

f F´(r) = 0          -12005*(1)/r^(2) + 514,58*r =0

-120005 + 514,58*^(3) = 0          514,58*^(3) = 12005      r =cubic root (23,32)

r = 2,85 ft

if we replace this value en F(r) we can see F(r) tend to infinite both when r tend to 0 and when r tends to infnite so there is a minimun for the functon

r = 2,85 ft    and   h = 8,56 ft

5 0
3 years ago
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