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3 years ago

The length of a rectangle is 5m longer than the width. If the perimeter of the rectangle is 58 m, find its length and width

Mathematics

1 answer:

LekaFEV [45]3 years ago

3 0

Answer:

L = 17 m W = 12 m

Step-by-step explanation:

Here is the answer.

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The radius of a circle is 14 meters. What is the circle circumference

seropon [69]

Step-by-step explanation:

HERE,

redius of a circle (r)=14 meters.

we know that,

$\boxed{\red{\sf{circle~ circumference=2\times \pi \times r }}}$

According to the question, 

circle circumference=

$\tt{2\times \pi \times 14 }$

$\tt{2 \times \dfrac{22}{7} \times 14 }$

$\tt{2 \times \dfrac{22}{\cancel{7}} \times \cancel{14}}$

$\tt{2\times 22 \times 2 }$

$\tt{ 88~meters }$

so, the circumference of that circle is 88 meters.

5 0

3 years ago

Choose the correct simplification of (7x^3y^3)^2. (5 points) 100 POINTS GIVING BRAINLIEST FOR GOOD EXPLANATION

In-s [12.5K]

Answer:

Option C

Step-by-step explanation:

(7x^3y^3)^2

= (7)^2 * (x^3)^2 * (y^3)^2

= 49 * x^(3*2) * y^(3*2)

= 49x^6y^6

You have to distribute the terms in "7x^3 * y^3" each to the power of 2

(7)^2 * (x^3)^2 * (y^3)^2

Now you can apply the rule "(x^a)^b = x^a*b" and further simplify the expression

4 0

3 years ago

Read 2 more answers

How can i describe the expression 3x−2 please help

svp [43]

Answer:

Step-by-step explanation:

3X-2=0

3X=2

X=2/3 OR X=0.66

7 0

4 years ago

Read 2 more answers

Marsha has three rugs.The first rug is 2 meters 87 centimeters long.The second rug has a length 98 centimeters less than the fir

Andrews [41]

There is a 13 centimeter difference between the first rug and the third rug. The first rug=287 centimeters and the third rug= 300 centimeters.

3 0

3 years ago

(A)using geometry vocabulary, describe a sequence of transformations that maps figure P (-1,2)(-1,4) (-4,2) (-4,4) onto figure Q

andrey2020 [161]

Before we proceed on determining the transformation happening on this problem, it's better to see first the location of the figure by drawing it in a cartesian coordinate plane. We have

If we observe the figures and the coordinates of the plot, we can see that there is a difference of 1 on the x coordinates of P and y coordinates of Q. Therefore, the first transformation that we consider here is the movement of figure P by 1 unit to the left. We have

$\begin{gathered} P_1=(-1-1,2_{})=(-2,2) \\ P_2=(-1-1,4)=(-2,4) \\ P_3=(-4-1,2)=(-5,2) \\ P_4=(-4-1,4)=(-5,4) \end{gathered}$

This transformation changes the location of figure P into

The next transformation will be the rotation of the red dotted figure on the figure above by 90 degrees counterclockwise. With this transformation, the coordinates will transform as

$P_{ccw,90}=(-y,x)$

Hence, for the rotation, we have the new coordinates.

$\begin{gathered} P_1^{\prime}=(-2,-2) \\ P_2^{\prime}=(-4,-2) \\ P_3^{\prime}=(-2,-5) \\ P_4^{\prime}=(-4,-5) \end{gathered}$

The transformed image, which is represented as NMPO, will now be at

For the last transformation, we will be reflecting the figure NMPO over the y axis. This changes the coordinates as

$P_{\text{rotation,y}-\text{axis}}=(-x,y)$

We now have the new coordinates:

$\begin{gathered} P^{\doubleprime}_1=(2,-2)=Q_1_{}_{} \\ P_2^{\doubleprime}=(4,-2)=Q_3 \\ P_3^{\doubleprime}=(2,-5)=Q_2 \\ P_4^{\doubleprime}_{}=(4,-5)=Q_4_{} \end{gathered}$

As you can see, they have the same coordinates as figure Q.

The mapping rules for the sequence described above are as follows:

First transformation (moving one unit to the left (x-1,y))

$\begin{gathered} P_1(-1,2)\rightarrow P_1(-1-1,2)\rightarrow P_1(-2,2) \\ P_2(-1,4)\rightarrow P_1(-1-1,4)\rightarrow P_2(-2,4) \\ P_3(-4,2)\rightarrow P_1(-4-1,2)\rightarrow P_3(-5,2) \\ P_4(-4,4)\rightarrow P_1(-4-1,4)\rightarrow P_4(-5,4) \end{gathered}$

Second transformation (rotation counter clockwise (-y,x))

$\begin{gathered} P_1(-2,2)\rightarrow P^{\prime}_1(-2,-2)_{} \\ P_2(-2,4)\rightarrow P^{\prime}_2(-4,-2) \\ P_3(-5,2)\rightarrow P^{\prime}_3(-2,-5)_{} \\ P_4(-5,4)\rightarrow P^{\prime}_4(-4,-5)_{} \end{gathered}$

Third Transformation (reflection over y-axis (-x,y))

$\begin{gathered} P^{\prime}_1(-2,-2)\rightarrow P^{\doubleprime}_1(-(-2),-2)\rightarrow P^{\doubleprime}_1=(2,-2)=Q_1 \\ P^{\prime}_2(-4,-2)\rightarrow P^{\doubleprime}_1(-(-4),-2)\rightarrow P^{\doubleprime}_1=(4,-2)=Q_3 \\ P^{\prime}_3(-2,-5)\rightarrow P^{\doubleprime}_1(-(-2),-5)\rightarrow P^{\doubleprime}_1=(2,-5)=Q_2 \\ P^{\prime}_4(-4,-5)\rightarrow P^{\doubleprime}_1(-(-4),-5)\rightarrow P^{\doubleprime}_1=(4,-5)=Q_4 \end{gathered}$

7 0

2 years ago