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bazaltina [42]
3 years ago
7

 They spent $18 on tickets to the carnival and $36 on food.  They spent the rest of the money on g They spent $18 on tickets

to the carnival and $36 on food.  They spent the rest of the money on games. ames.
Mathematics
1 answer:
Reptile [31]3 years ago
8 0

Answer:

93 = g + 36 + 18

Step-by-step explanation:

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Beth solved the system of equations by making a substitution for y in the second equation. What equation did she get as a result
Slav-nsk [51]
Hello there!

The correct answer is option C

3x + 20x - 55 = -9


I am not sure if you wanted some more details but I hope this helps and if you do, just let me and I will edit it.

Good luck with your studies!

Happy New Year!~
3 0
2 years ago
State the domain and range in set notation​
antiseptic1488 [7]

Answer:

Image result for State the domain and range in set notation​

The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values).

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

with magnitude \sqrt{1^2+2^2+1^2}=\sqrt6. The integral of f(x,y,z)=e^z over S is then

\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
3 years ago
Select the correct answer.
likoan [24]

Answer:

x = 20

Step-by-step explanation:

Traingle ABC = Traingle DEC

4x-1×4×5 = x+2×4×5

80x-1 = 2×20x

80x-20x = 2+1

60x = 3

60÷3 = x

x = 20

6 0
3 years ago
1. Use the following graph to determine the coordinated of the y-intercept.
jarptica [38.1K]

Answer:

I believe it's C. (0.4)

Step-by-step explanation:

6 0
2 years ago
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