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Ray Of Light [21]
3 years ago
13

Jane is designing a print brochure for a retail company. She’s having trouble deciding on the page margin. Which best practice w

ould you advise Jane to implement?
A. Keep the bottom margin larger than any other margins
B. Keep the left margin larger than any other margins
C. Keep the right margin smaller than any other margins
D. Keep the top margin larger than any other margins
E. Keep the top and left margin is equal bit larger than other margins
Computers and Technology
2 answers:
8090 [49]3 years ago
7 0

I think the answer will be C

Karo-lina-s [1.5K]3 years ago
5 0
D is the answer for this problem
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Read 2 more answers
given an array of integers a, your task is to count the number of pairs i and j (where 0 ≤ i < j < a.length), such that a[
Nimfa-mama [501]

Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.

<h3>Writting the code:</h3>

<em>// C++ program for the above approach</em>

<em> </em>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em> </em>

<em>// Function to find the count required pairs</em>

<em>void getPairs(int arr[], int N, int K)</em>

<em>{</em>

<em>    // Stores count of pairs</em>

<em>    int count = 0;</em>

<em> </em>

<em>    // Traverse the array</em>

<em>    for (int i = 0; i < N; i++) {</em>

<em> </em>

<em>        for (int j = i + 1; j < N; j++) {</em>

<em> </em>

<em>            // Check if the condition</em>

<em>            // is satisfied or not</em>

<em>            if (arr[i] > K * arr[j])</em>

<em>                count++;</em>

<em>        }</em>

<em>    }</em>

<em>    cout << count;</em>

<em>}</em>

<em> </em>

<em>// Driver Code</em>

<em>int main()</em>

<em>{</em>

<em>    int arr[] = { 5, 6, 2, 5 };</em>

<em>    int N = sizeof(arr) / sizeof(arr[0]);</em>

<em>    int K = 2;</em>

<em> </em>

<em>    // Function Call</em>

<em>    getPairs(arr, N, K);</em>

<em> </em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ4

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Help me understand why it does not loop correctly and how to make the converter a continious loop? What am I doing wrong and how
Aleksandr-060686 [28]

Answer:

The control loop responds to

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Explanation:

If you are trying to make a loop run a certain number of time in Python, then...

To repeat something a certain number of times, you may:

1. Use range or xrange for i in range(n): # do something here.

2. Use while i = 0 while i < n: # do something here i += 1.

3. If the loop variable i is irrelevant, you may use _ instead for _ in range(n): # do something here _ = 0 while _ < n # do something here _ += 1.

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