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rodikova [14]
4 years ago
13

Factor completely X⁴-10x²+9. Please show all work.​

Mathematics
1 answer:
Tanya [424]4 years ago
3 0

Answer:

Let y=x² . Then:

x4−10x2+9=y2−10y+9

y²-10y+9=(y-9)(y-1)

Substitute x² for y:

x4−10x2+9=(x2−9)(x2−1)

x²-9=(x+3)(x-3)

x²-1=(x+1)(x-1)

x4−10x2+9=(x+3)(x−3)(x+1)(x−1)

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Let f(x)= 2x-3/9 and g(x)=9x+3/2<br><br> Find (f o g)(x)<br> Find (f o g)(x)
svlad2 [7]
These seem tough, but they are not that bad. 
(f o g)(x)

That means to take function g when x = x (It just means that you don't need to do anything with the function) and substitute it into function f wherever there is a x value. (So basically g becomes what x equals) 
Here is a visual representation of it.

(f o g)(x) = 2(9x + (3/2)) - (3/9) 

We need to distribute the 2 to everything inside the parenthesis.

(f o g)(x) = 18x + (6/2) - (3/9) 

Let's simplify the fraction on the right and left, then find a common denominator so we can add / subtract the two fractions. 

(f o g)(x) = 18x + (3) - (1/3) 
(f o g)(x) = 18x + (9/3) - (1/3) 

Combine like terms.

(f o g)(x) = 18x + (8/3)

Our final answer is: 
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8 0
3 years ago
If the cost of an item increased by a percentage and decreased by the same percentage, what would that percentage be if the new
Orlov [11]

The percentage, if the new cost was 84% of the original is 40%

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New =x \times (1 + y\%) \times (1 - y\%)

The cost is said to be 84% of the original price.

So, we have:

x \times (1 + y\%) \times (1 - y\%) =84\% \times x

Divide both sides by x

(1 + y\%) \times (1 - y\%) =84\%

Apply the difference of two squares

1 - (y\%)^2 =84\% \\\\

Subtract 1 from both sides of the equation

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Cancel out the common factors

(y\%)^2 =16\%

Take the square root of both sides

y\% =0.4

Multiply both sides by 100

y =40

Hence, the percentage is 40%

Read more about percentage change at:

brainly.com/question/809966

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3 years ago
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son4ous [18]
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Answer:

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