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ivolga24 [154]
3 years ago
9

Length = 7.5 Width = 5 Height = 1 Surface Area = 100 inches squared Shape = rectangular prism or box What is the surface area of

the box if it is scaled up by a factor of 10? Please help! 50 points!

Mathematics
1 answer:
liberstina [14]3 years ago
4 0

Step-by-step explanation:

hete is your formula this u can find answer

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1. The quadratic parent function f(x) = x2 was transformed to
AlekseyPX

Answer:

C

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

The graph of g(x) is the graph of f(x) shifted 6 units left , then

g(x) = f(x + 6) → C

7 0
3 years ago
If 1/4<br> inch equals 50 miles, find the miles represented by 4 1/2<br> inches.
Lostsunrise [7]

Answer:

900 miles

Step-by-step explanation:

Well, 200 miles is 1 inch. 100 miles is 1/2 an inch.

3 0
4 years ago
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Please show how 1200.00 is an estimate of 31×43?
Vika [28.1K]
Ok so you round 31 to 30 and 43 to 40 and then you multiply 30 by 40 and get 1200. 1200 is the same thing as 1200.00 bc you can take off the zeros after the decimal and it will be the same. Hope this helped and if your still confused you let me know I'll try to explain it more.
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3 years ago
Simplify<br> -4 1/5 (-13 1/10)<br> pls help
oksian1 [2.3K]

Answer:

55 1/50 or 2751/50

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Convert both expressions to improper form

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4 0
3 years ago
Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at
sweet [91]

Answer:  The answer is 35 minutes.


Step-by-step explanation:  Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

In 9 minutes, distance run by Gavin = 1 mile.

So, in 1 minute, distance travelled by Gavin will be

d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.

Now, difference between Lars and Gavin's rate of runnings is

\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.

Therefore, the time taken by Lars to reach Gavin is given by

t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.

Thus, the required time is 365 minutes.  


6 0
3 years ago
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