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galben [10]
3 years ago
8

You are considering two brands of spaghetti noodles. The first brand weighs 1.5 lb and costs $2.30. The second brand weighs 2 lb

and costs $3.30. Which brand is the better deal per pound?
A Brand 1 is the better deal.

B Brand 2 is the better deal.

C Both brands cost the same per pound.

D There is not enough information provided to answer the question.
Mathematics
2 answers:
Nikolay [14]3 years ago
8 0

Answer: A brand 1 is the better deal

Step-by-step explanation:

First divide 2.3 by 1.5 =1 8/15

And divide 3.3 by 2 and get 1 13/20 so the first one is less than the second one

alukav5142 [94]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Brand A has a lower price per pound by about .10 cents

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Find 35% of 65, since A= 35 and B= 65.  

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Multiply that by 65, for the percentage.

65*.35= 22.75

So, 35% of 65= 22.75

22.75 is not equal to 35.

This statement is false.

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3 years ago
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3 years ago
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3 years ago
When testing a hypothesis about a single mean, a sample size of 200 is selected from a normally distributed population. If the p
Evgen [1.6K]

Answer:

Null hypothesis:\mu \leq \mu_o  

Alternative hypothesis:\mu > \mu_o  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Step-by-step explanation:

Data given and notation  

\bar X represent the sample mean

\sigma represent the population standard deviation for the sample  

n=200 sample size  

\mu_o represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to \mu_o, the system of hypothesis would be:  

Null hypothesis:\mu \leq \mu_o  

Alternative hypothesis:\mu > \mu_o  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

5 0
4 years ago
Use an algebraic approach to solve the problem.
qaws [65]

Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

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Use the formula for the mean: sum of elements / number of elements

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Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 =  ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

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So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

6 0
3 years ago
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